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Help in finding Value in Index Array
That works!
Thank you both very much. "RagDyer" wrote: Works OK for me! -- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- "Peo Sjoblom" wrote in message ... That formula does not work for me,it fails if G5 is zero -- Regards, Peo Sjoblom "RagDyer" wrote in message ... Try this *array* formula: =INDEX(INDEX(G5:G40,MATCH(TRUE,C5:C40=0,0)):G40, MATCH(TRUE,INDEX(G5:G40,MATCH(TRUE,C5:C40=0,0)):G4 00,0)) -- Array formulas must be entered with CSE, <Ctrl <Shift <Enter, instead of the regular <Enter, which will *automatically* enclose the formula in curly brackets, which *cannot* be done manually. Also, you must use CSE when revising the formula. -- HTH, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- "George" wrote in message ... It now shows #N/A. Could it be because Column G has blank (empty cell) rows before the first positive value? "Peo Sjoblom" wrote: Try this =INDEX(G5:G400,MATCH(TRUE,INDEX(INDEX(G5:G400,MATC H(TRUE,C5:C400="",0)):G400,0)0,0)+MATCH(TRUE,C5:C 400="",0)-1) array entered -- Regards, Peo Sjoblom "George" wrote in message ... I am looking for the first positive value in column G (not C), after the first empty cell in column C. (I tried just replacing the C & G's but it didn't work.) "Peo Sjoblom" wrote: Either I totally misunderstood what you wanted or you are not using the same cell references/formula as posted because it does return the first value in C5:C400 greater than zero starting from the first blank cell in G5:G500. This is what I have starting in G5 0 8 7 6 5 4 3 2 1 0 -1 -2 -3 -4 -5 -6 -7 8 9 so the first blank is below -7 in C22, this is what I have starting in C5 0 -17 -16 -15 1 -13 -12 16 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 0 0 0 0 5 6 7 8 9 10 the first value greater than 0 starting in row C22 is 5 in cell C28 and that is what my formula returns -- Regards, Peo Sjoblom "George" wrote in message ... Hi Peo, Sorry but that returns the C5 value (column G is zero at that point, if it helps). I need the first positive number in column G after column C is empty. Thanks, "Peo Sjoblom" wrote: I misunderstood, I thought you were looking for zero in column G, this will work =INDEX(C5:C400,MATCH(TRUE,INDEX(INDEX(C5:C400,MATC H(TRUE,G5:G400="",0)):C400,0)0,0)+MATCH(TRUE,G5:G 400="",0)-1) -- Regards, Peo Sjoblom "George" wrote in message ... Hi Peo, Thanks, but the formula below returns the first value in column C (after row 5), but I am actually looking for the first positive value in column G after column C declines to an empty cell. "Peo Sjoblom" wrote: One way =INDEX(C5:C400,MATCH(TRUE,INDEX(INDEX(C5:C400,MATC H(1,(G5:G400=0)*(G5:G400<""),0)):C400,0)0,0)+MAT CH(1,(G5:G400=0)*(G5:G400<""),0)-1) entered with ctrl + shift & enter -- Regards, Peo Sjoblom "George" wrote in message ... I am trying to search a column (C5:C400) to find out when it runs to a null value, then search down a different column (G) starting from that same row and return the first positive number found. Can anyone help? I've been using the following as a starting point, but I'm stuck on how to complete it. =INDEX(MATCH(TRUE,G5:G4000),MATCH(TRUE,C5:C400=0, 0)) Thanks! |
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