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#1
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Scattergraph: Meaningful interpretation
I made a scattergraph (Car price Y; Km X). It is ok for comparison at say a given level of Km, but as prices are scaled from $4000 to $7500 and 0 to 120 kliometers it is a little artificial in so far as an extra $1000 might get a car that has done 40,000 fewer km .
I'm wondering what statistical/ mathematical measures I might use to squeeze more out of the data. Hope that's not confusing, thanks John |
#2
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Scattergraph: Meaningful interpretation
John -
One suggestion: Explain the variation in price using more explanatory variables (i.e., other characteristics of the cars). Use multiple regression. - Mike www.MikeMiddleton.com "JohnH" wrote in message ... I made a scattergraph (Car price Y; Km X). It is ok for comparison at say a given level of Km, but as prices are scaled from $4000 to $7500 and 0 to 120 kliometers it is a little artificial in so far as an extra $1000 might get a car that has done 40,000 fewer km . I'm wondering what statistical/ mathematical measures I might use to squeeze more out of the data. Hope that's not confusing, thanks John |
#3
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Scattergraph: Meaningful interpretation
On Sat, 30 Jun 2007, in microsoft.public.excel.charting,
JohnH said: I made a scattergraph (Car price Y; Km X). It is ok for comparison at say a given level of Km, but as prices*are scaled*from* $4000 to $7500* and 0 to 120 kliometers it is a little artificial in so far as an extra $1000 might get a car that has done 40,000 fewer km . * *I'm wondering what statistical/ mathematical measures I might use to squeeze more out of the data. You could use the "Exponential" trendline type in the chart to calculate a dollars per mile marginal depreciation rate. The trendline equation that is displayed looks like this y = e^[some number]x The number (which we'll call K) will probably be negative if the cars are getting cheaper the more miles they have. The equation is another way of saying cost = exp(K times mileage) or ln(cost) = K times mileage Copy the number K, including the negative sign (don't forget to get lots of digits! the more the better) and paste it back into a cell in your spreadsheet. K is the average marginal depreciation, in dollars per mile, of the cars *by cost*. dollars cheaper/extra mile = K times cost Since that's a little awkward (you'd rather have the depreciation for a car of miles travelled), you want to convert the cost into mileage using the same equation as above dollars cheaper/extra mile = K times exp(K times mileage) It's okay for K to appear twice in that equation, that's not a mistake. Now you should be able to look at a car of 100,000 miles, and guess how many dollars value it would lose by running another 10,000 miles. Of course, different models of car would have different depreciation rates. If your database is big enough, you might like to calculate a different depreciation for every model of car. If you don't want to use the trendline, you can use LINEST() to get K from a column of LN(cost) against a column of mileage. If you're not sure you got the right number, you can check to see if LINEST and the trendline are giving the same answers. -- Del Cotter NB Personal replies to this post will send email to , which goes to a spam folder-- please send your email to del3 instead. |
#4
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Scattergraph: Meaningful interpretation
Thanks for the suggestions, I'll give it a go. I also thought of guestimating the life of a car, subtracting km travelled and dividing by the price to estimate the km's bought for each dollar??
John "JohnH" wrote in message ... I made a scattergraph (Car price Y; Km X). It is ok for comparison at say a given level of Km, but as prices are scaled from $4000 to $7500 and 0 to 120 kliometers it is a little artificial in so far as an extra $1000 might get a car that has done 40,000 fewer km . I'm wondering what statistical/ mathematical measures I might use to squeeze more out of the data. Hope that's not confusing, thanks John |
#5
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Scattergraph: Meaningful interpretation
On Sun, 1 Jul 2007, in microsoft.public.excel.charting,
JohnH said: Thanks for the suggestions, I'll give it a go. Be aware that I made a mistake and forgot a second variable, the constant that occurs when mileage is zero. So there are two variables to find. -- Del Cotter NB Personal replies to this post will send email to , which goes to a spam folder-- please send your email to del3 instead. |
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