You have good answers to your questions but I think you should know that
there is an antilog.

The log (base 10 for simplicity) function is defined thus: IF X = 10^Y then
LOG(X)=Y
Try it with 100. Since 100=10^2 we write LOG(100)=2

So if we know that Y is the LOG of X, we find X using 10^Y
What is the antilog of 2? Clearly it is 10^2 or 100

In brief ANTILOG(Y) is the same as 10^Y

Sorry for the lecture but I retired recently and miss the classroom!

best wishes
Bernard



"Keithg" wrote in message
...
I need to calculate the 9th root of a number. If I go the route of log()/9,
there is no function for antilog. Anybody help?