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I am looking to find out if there is a way to do this:
I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#2
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Hi Mike
If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#3
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Hi, sorry, but that doesn't make sense to me. I am going to enter in
different values in d1 through d9, but the formula where I divide 88/(the furthest number to the right out of d1-d9). If I put in a match formula in d1-9, then I won't be able to have a value... right? "Roger Govier" wrote: Hi Mike If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#4
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You already know that the furthest number is 88?
Is it the numerator or the denominator? How about a more explicit explanation, with examples of data and exactly what you're looking to accomplish? -- Regards, RD ---------------------------------------------------------------------------- ------------------- Please keep all correspondence within the Group, so all may benefit ! ---------------------------------------------------------------------------- ------------------- "Mike" wrote in message ... Hi, sorry, but that doesn't make sense to me. I am going to enter in different values in d1 through d9, but the formula where I divide 88/(the furthest number to the right out of d1-d9). If I put in a match formula in d1-9, then I won't be able to have a value... right? "Roger Govier" wrote: Hi Mike If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#5
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yes, sorry. I should have filled in the spaces a little bit. I am making a
spreadsheet for an office competition. We are having a weight loss competition over the next 3 months with weekly weigh-ins every monday. Basically, we're competing based on percentage of weight lost, and every week I want the percentage to be updated based on the new weight. So, I have 13 weeks where I'm going to be inputing the new numbers for each person. I don't want to go in and change the formula each week to be up to date with the new weight, so I was hoping that there was a way for excel to take the value in the furthest right cell in a row. The formula will be something like this (100%-(Cell furthest to the right between g4:s4)/(original weight)). That will give me the percentage of weight lost... I hope this makes a little more sense... and thank you so much for your help! "RagDyeR" wrote: You already know that the furthest number is 88? Is it the numerator or the denominator? How about a more explicit explanation, with examples of data and exactly what you're looking to accomplish? -- Regards, RD ---------------------------------------------------------------------------- ------------------- Please keep all correspondence within the Group, so all may benefit ! ---------------------------------------------------------------------------- ------------------- "Mike" wrote in message ... Hi, sorry, but that doesn't make sense to me. I am going to enter in different values in d1 through d9, but the formula where I divide 88/(the furthest number to the right out of d1-d9). If I put in a match formula in d1-9, then I won't be able to have a value... right? "Roger Govier" wrote: Hi Mike If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#6
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Hi Mike
You are wanting the value in the cell furthest right from D1, not the cell location, so change the formula to =LOOKUP(9.99999999999999E+307,1:1) e.g. =(88/LOOKUP(9.99999999999999E+307,1:1)) Obviously, which cell you put the formula in is up to you (I agree, not in D,1 although my wording was totally unclear, I mean't this would give the value relative to D1). If you are wanting the formula to go on the same row, and your data does not extend beyond say column N, then in O1 =(88/LOOKUP(9.99999999999999E+307,D1:N1)) -- Regards Roger Govier Mike wrote: Hi, sorry, but that doesn't make sense to me. I am going to enter in different values in d1 through d9, but the formula where I divide 88/(the furthest number to the right out of d1-d9). If I put in a match formula in d1-9, then I won't be able to have a value... right? "Roger Govier" wrote: Hi Mike If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#7
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Awesome, that worked! Sorry for all the confusion. I'm currious though,
would you mind explaining to me the 9.99999 part? "Roger Govier" wrote: Hi Mike You are wanting the value in the cell furthest right from D1, not the cell location, so change the formula to =LOOKUP(9.99999999999999E+307,1:1) e.g. =(88/LOOKUP(9.99999999999999E+307,1:1)) Obviously, which cell you put the formula in is up to you (I agree, not in D,1 although my wording was totally unclear, I mean't this would give the value relative to D1). If you are wanting the formula to go on the same row, and your data does not extend beyond say column N, then in O1 =(88/LOOKUP(9.99999999999999E+307,D1:N1)) -- Regards Roger Govier Mike wrote: Hi, sorry, but that doesn't make sense to me. I am going to enter in different values in d1 through d9, but the formula where I divide 88/(the furthest number to the right out of d1-d9). If I put in a match formula in d1-9, then I won't be able to have a value... right? "Roger Govier" wrote: Hi Mike If the data is numeric, then for D1 =MATCH(9.99999999999999E+307,1:1) if it is text then =MATCH(REPT("Z",255),1:1) Copy down and it will alter for rows 2:9 -- Regards Roger Govier Mike wrote: I am looking to find out if there is a way to do this: I have a vector of values say (D1:D9) witch equal different weeks. I fill in a cell each week starting with D1, and after 9 weeks I fill in D9. I need to create a formula that will find the furthest cell to the right to make my solution accurate. Basically, I have a constant number witch is integrated into the formula, but my variable will change... and hopefully automatically based on it being the furthest cell to the right or whatever the technical way of saying it would be. Thanks for your help! |
#8
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