View Single Post
  #7   Report Post  
Posted to microsoft.public.excel.worksheet.functions
Mike
 
Posts: n/a
Default Index, Lookup and Vectors/Arrays

Awesome, that worked! Sorry for all the confusion. I'm currious though,
would you mind explaining to me the 9.99999 part?

"Roger Govier" wrote:

Hi Mike

You are wanting the value in the cell furthest right from D1, not the
cell location, so change the formula to
=LOOKUP(9.99999999999999E+307,1:1)

e.g. =(88/LOOKUP(9.99999999999999E+307,1:1))

Obviously, which cell you put the formula in is up to you (I agree, not
in D,1 although my wording was totally unclear, I mean't this would give
the value relative to D1).

If you are wanting the formula to go on the same row, and your data does
not extend beyond say column N, then in O1
=(88/LOOKUP(9.99999999999999E+307,D1:N1))

--
Regards

Roger Govier



Mike wrote:
Hi, sorry, but that doesn't make sense to me. I am going to enter in
different values in d1 through d9, but the formula where I divide
88/(the furthest number to the right out of d1-d9). If I put in a
match formula in d1-9, then I won't be able to have a value... right?

"Roger Govier" wrote:

Hi Mike

If the data is numeric, then for D1
=MATCH(9.99999999999999E+307,1:1)
if it is text then
=MATCH(REPT("Z",255),1:1)
Copy down and it will alter for rows 2:9

--
Regards

Roger Govier



Mike wrote:
I am looking to find out if there is a way to do this:

I have a vector of values say (D1:D9) witch equal different weeks.
I fill in a cell each week starting with D1, and after 9 weeks I
fill in D9. I need to create a formula that will find the furthest
cell to the right to make my solution accurate.

Basically, I have a constant number witch is integrated into the
formula, but my variable will change... and hopefully automatically
based on it being the furthest cell to the right or whatever the
technical way of saying it would be.

Thanks for your help!