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#1
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if/countif for 12 different arguments
I'm trying to write an if/countif function for the following situation:
if column L has the 2nd and 3rd #s that are "01" then write "01" in column M if column L has the 2nd and 3rd #s that are "02" then write "02" in column M, etc. all the way to 12. (01, 02,....12 standing for the days of the month.) I wrote: if(countif(L3,"?01*"),"01",if(countif(L3,"?02*")," 02",if(countif(L3,"?03*"),"03", etc. but it's wrong b/c I don't know how to write a long if function. Can someone help? |
#2
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if/countif for 12 different arguments
So, you basically just want to return the 2nd and 3rd characters from the
string in column L? Try this: =MID(L3,2,2) HTH, Elkar "Studebaker" wrote: I'm trying to write an if/countif function for the following situation: if column L has the 2nd and 3rd #s that are "01" then write "01" in column M if column L has the 2nd and 3rd #s that are "02" then write "02" in column M, etc. all the way to 12. (01, 02,....12 standing for the days of the month.) I wrote: if(countif(L3,"?01*"),"01",if(countif(L3,"?02*")," 02",if(countif(L3,"?03*"),"03", etc. but it's wrong b/c I don't know how to write a long if function. Can someone help? |
#3
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if/countif for 12 different arguments
Are these dates you're working with?
What's in L3? You'll need to show us some examples. -- Biff Microsoft Excel MVP "Studebaker" wrote in message ... I'm trying to write an if/countif function for the following situation: if column L has the 2nd and 3rd #s that are "01" then write "01" in column M if column L has the 2nd and 3rd #s that are "02" then write "02" in column M, etc. all the way to 12. (01, 02,....12 standing for the days of the month.) I wrote: if(countif(L3,"?01*"),"01",if(countif(L3,"?02*")," 02",if(countif(L3,"?03*"),"03", etc. but it's wrong b/c I don't know how to write a long if function. Can someone help? |
#4
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if/countif for 12 different arguments
That is so Cool!
And it works with letter's as well! What are some of the boundaries of this equation? -- Thanks and God bless you and yours, Gabriella777_2 "Elkar" wrote: So, you basically just want to return the 2nd and 3rd characters from the string in column L? Try this: =MID(L3,2,2) HTH, Elkar "Studebaker" wrote: I'm trying to write an if/countif function for the following situation: if column L has the 2nd and 3rd #s that are "01" then write "01" in column M if column L has the 2nd and 3rd #s that are "02" then write "02" in column M, etc. all the way to 12. (01, 02,....12 standing for the days of the month.) I wrote: if(countif(L3,"?01*"),"01",if(countif(L3,"?02*")," 02",if(countif(L3,"?03*"),"03", etc. but it's wrong b/c I don't know how to write a long if function. Can someone help? |
#5
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if/countif for 12 different arguments
That's exactly what I needed. Thank you so much!
"Elkar" wrote: So, you basically just want to return the 2nd and 3rd characters from the string in column L? Try this: =MID(L3,2,2) HTH, Elkar "Studebaker" wrote: I'm trying to write an if/countif function for the following situation: if column L has the 2nd and 3rd #s that are "01" then write "01" in column M if column L has the 2nd and 3rd #s that are "02" then write "02" in column M, etc. all the way to 12. (01, 02,....12 standing for the days of the month.) I wrote: if(countif(L3,"?01*"),"01",if(countif(L3,"?02*")," 02",if(countif(L3,"?03*"),"03", etc. but it's wrong b/c I don't know how to write a long if function. Can someone help? |
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