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#1
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consecutive numbers
I want to have a column which has a formula which multiplies an absolute cell
by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#2
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consecutive numbers
=ROW(A1)*$A$4, and copy down.
-- David Biddulph "Phippsy" wrote in message ... I want to have a column which has a formula which multiplies an absolute cell by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#3
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consecutive numbers
I had thought of that but it doesn't necessarily start in row 1 so I have got
past that by maybe using ROW(A1)-4 if it starts in row 5 for example but then it would not work if rows were inadvertently added above so was wondering if there was a safer formula? Debbie "David Biddulph" wrote: =ROW(A1)*$A$4, and copy down. -- David Biddulph "Phippsy" wrote in message ... I want to have a column which has a formula which multiplies an absolute cell by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#4
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consecutive numbers
Debbie,
Row(A1) will return 1 no matter what cell you start in. It will increment to Row(A2) - which will return 2 - when incremented. If you want to make sure that you can insert rows without affecting your formula, use =(ROW()-ROW($A$5)+1)*$A$4 where the formula is entered into a cell on row 5. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... I had thought of that but it doesn't necessarily start in row 1 so I have got past that by maybe using ROW(A1)-4 if it starts in row 5 for example but then it would not work if rows were inadvertently added above so was wondering if there was a safer formula? Debbie "David Biddulph" wrote: =ROW(A1)*$A$4, and copy down. -- David Biddulph "Phippsy" wrote in message ... I want to have a column which has a formula which multiplies an absolute cell by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#5
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consecutive numbers
Of course!! What a ninny I am.
Thanks "Bernie Deitrick" wrote: Debbie, Row(A1) will return 1 no matter what cell you start in. It will increment to Row(A2) - which will return 2 - when incremented. If you want to make sure that you can insert rows without affecting your formula, use =(ROW()-ROW($A$5)+1)*$A$4 where the formula is entered into a cell on row 5. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... I had thought of that but it doesn't necessarily start in row 1 so I have got past that by maybe using ROW(A1)-4 if it starts in row 5 for example but then it would not work if rows were inadvertently added above so was wondering if there was a safer formula? Debbie "David Biddulph" wrote: =ROW(A1)*$A$4, and copy down. -- David Biddulph "Phippsy" wrote in message ... I want to have a column which has a formula which multiplies an absolute cell by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#6
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consecutive numbers
Another one:
=ROWS($1:1)*$A$4 -- Biff Microsoft Excel MVP "Phippsy" wrote in message ... Of course!! What a ninny I am. Thanks "Bernie Deitrick" wrote: Debbie, Row(A1) will return 1 no matter what cell you start in. It will increment to Row(A2) - which will return 2 - when incremented. If you want to make sure that you can insert rows without affecting your formula, use =(ROW()-ROW($A$5)+1)*$A$4 where the formula is entered into a cell on row 5. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... I had thought of that but it doesn't necessarily start in row 1 so I have got past that by maybe using ROW(A1)-4 if it starts in row 5 for example but then it would not work if rows were inadvertently added above so was wondering if there was a safer formula? Debbie "David Biddulph" wrote: =ROW(A1)*$A$4, and copy down. -- David Biddulph "Phippsy" wrote in message ... I want to have a column which has a formula which multiplies an absolute cell by a number which increases incrementally. =1*$A$4 =2*$A$4 etc. up to about 100. How can I enter the consecutive number into the formula so I can replicate it? I don't want an extra column with the numbers 1-100! Thanks |
#7
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consecutive numbers
"T. Valko" wrote...
Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#8
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consecutive numbers
If I do this
=ROWS($1:1)*$A$4 Then insert a row above it all goes up the creak. I am not sure I understand this function but I do understand the ROW() function Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#9
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consecutive numbers
The last one I understand having looked what the ROWS function does however
why is this better than using the ROW() function? Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#10
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consecutive numbers
Phippsy,
As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... The last one I understand having looked what the ROWS function does however why is this better than using the ROW() function? Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#11
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consecutive numbers
If I enter this formula in B2:
=ROWS($1:1)*$A$4 Then insert a new row 1, the formula correctly changes the references to: =ROWS($2:2)*$A$5 Which is the equivalent of: =1*$A$5 How does inserting a new row above the formula cell mess up the ROWS function? -- Biff Microsoft Excel MVP "Bernie Deitrick" <deitbe @ consumer dot org wrote in message ... Phippsy, As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... The last one I understand having looked what the ROWS function does however why is this better than using the ROW() function? Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#12
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consecutive numbers
"Bernie Deitrick" <deitbe @ consumer dot org wrote...
As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. .... Consider the formulas currently on offer with the *$A$4 pruned away, entered into A5 (Bernie's), C5 (Biff's) and E5 (mine) and all filled down into the next 5 rows. Bernie's: A5: =ROW()-ROW($A$5)+1 returns 1 A6: =ROW()-ROW($A$5)+1 returns 2 A7: =ROW()-ROW($A$5)+1 returns 3 A8: =ROW()-ROW($A$5)+1 returns 4 A9: =ROW()-ROW($A$5)+1 returns 5 A10: =ROW()-ROW($A$5)+1 returns 6 Biff's: C5: =ROWS($1:1) returns 1 C6: =ROWS($1:2) returns 2 C7: =ROWS($1:3) returns 3 C8: =ROWS($1:4) returns 4 C9: =ROWS($1:5) returns 5 C10: =ROWS($1:6) returns 6 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: =ROWS(E$5:E7) returns 3 E8: =ROWS(E$5:E8) returns 4 E9: =ROWS(E$5:E9) returns 5 E10: =ROWS(E$5:E10) returns 6 Insert cells above A1:E2. These become Bernie's: A7: =ROW()-ROW($A$7)+1 returns 1 A8: =ROW()-ROW($A$7)+1 returns 2 A9: =ROW()-ROW($A$7)+1 returns 3 A10: =ROW()-ROW($A$7)+1 returns 4 A11: =ROW()-ROW($A$7)+1 returns 5 A12: =ROW()-ROW($A$7)+1 returns 6 Biff's: C7: =ROWS($1:1) returns 1 C8: =ROWS($1:2) returns 2 C9: =ROWS($1:3) returns 3 C10: =ROWS($1:4) returns 4 C11: =ROWS($1:5) returns 5 C12: =ROWS($1:6) returns 6 mine: E7: =ROWS(E$7:E7) returns 1 E8: =ROWS(E$7:E8) returns 2 E9: =ROWS(E$7:E9) returns 3 E10: =ROWS(E$7:E10) returns 4 E11: =ROWS(E$7:E11) returns 5 E12: =ROWS(E$7:E12) returns 6 No differences so far. Undo that cell insertion. Now insert cells above A7:E8, that is, within these formula ranges. These formulas become Bernie's: A5: =ROW()-ROW($A$5)+1 returns 1 A6: =ROW()-ROW($A$5)+1 returns 2 A7: <blank A8: <blank A9: =ROW()-ROW($A$5)+1 returns 5 A10: =ROW()-ROW($A$5)+1 returns 6 A11: =ROW()-ROW($A$5)+1 returns 7 A12: =ROW()-ROW($A$5)+1 returns 8 Biff's: C5: =ROWS($1:1) returns 1 C6: =ROWS($1:2) returns 2 C7: <blank C8: <blank C9: =ROWS($1:3) returns 3 C10: =ROWS($1:4) returns 4 C11: =ROWS($1:5) returns 5 C12: =ROWS($1:6) returns 6 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: <blank E8: <blank E9: =ROWS(E$5:E9) returns 5 E10: =ROWS(E$5:E10) returns 6 E11: =ROWS(E$5:E11) returns 7 E12: =ROWS(E$5:E12) returns 8 Debatable whether Biff's formulas are still correct and the others wrong or vice versa, but there's no differences in the results of Bernie's and my formulas. Undo that cell insertion and change to inserting entire rows, but it'll produce the same results. So Biff's formulas can behave differently than Bernie's and mine. Bernie's and mine will behave the same with respect to cell or row insertion. However, they'll behave differently with respect to row DELETION. Bernie's: A5: =ROW()-ROW(#REF!)+1 returns #REF! A6: =ROW()-ROW(#REF!)+1 returns #REF! A7: =ROW()-ROW(#REF!)+1 returns #REF! A8: =ROW()-ROW(#REF!)+1 returns #REF! A9: =ROW()-ROW(#REF!)+1 returns #REF! Biff's: C5: =ROWS($1:2) returns 2 C6: =ROWS($1:3) returns 3 C7: =ROWS($1:4) returns 4 C8: =ROWS($1:4) returns 4 C9: =ROWS($1:5) returns 5 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: =ROWS(E$5:E7) returns 3 E8: =ROWS(E$5:E8) returns 4 E9: =ROWS(E$5:E9) returns 5 Bigtime differences now. So I may grant that Biff's ROWS($1:#) formula isn't as robust as Bernie's ROW()-ROW(base_cell)+1 formula, but Bernie's formula isn't as robust as my ROWS(base_cell:current_cell) formula. If you don't believe me, find an actual example of INSERTING cells/rows that would produce different results for Bernie's and my formulas. I've already provided one that shows they differ when DELETING cells/rows. Then there's the simple fact that shorter formulas with one function call are usually better (as in faster, less error-prone) than longer formulas with multiple function calls. |
#13
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consecutive numbers
It is simpler to use ROWS than using ROW the way you do since you need two
row functions, one to offset any possible inserted rows on top thus you need to use a cell in the same row as the formula to "anchor" it. I always use it the same way as in Harlan's example and I find it much easier to use and as he showed it also adapts to row deletion so then we can also say it is better than using ROW -- Regards, Peo Sjoblom "Bernie Deitrick" <deitbe @ consumer dot org wrote in message ... Phippsy, As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... The last one I understand having looked what the ROWS function does however why is this better than using the ROW() function? Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
#14
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consecutive numbers
"Harlan Grove" wrote in message
ups.com... "Bernie Deitrick" <deitbe @ consumer dot org wrote... As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. ... Consider the formulas currently on offer with the *$A$4 pruned away, entered into A5 (Bernie's), C5 (Biff's) and E5 (mine) and all filled down into the next 5 rows. Bernie's: A5: =ROW()-ROW($A$5)+1 returns 1 A6: =ROW()-ROW($A$5)+1 returns 2 A7: =ROW()-ROW($A$5)+1 returns 3 A8: =ROW()-ROW($A$5)+1 returns 4 A9: =ROW()-ROW($A$5)+1 returns 5 A10: =ROW()-ROW($A$5)+1 returns 6 Biff's: C5: =ROWS($1:1) returns 1 C6: =ROWS($1:2) returns 2 C7: =ROWS($1:3) returns 3 C8: =ROWS($1:4) returns 4 C9: =ROWS($1:5) returns 5 C10: =ROWS($1:6) returns 6 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: =ROWS(E$5:E7) returns 3 E8: =ROWS(E$5:E8) returns 4 E9: =ROWS(E$5:E9) returns 5 E10: =ROWS(E$5:E10) returns 6 Insert cells above A1:E2. These become Bernie's: A7: =ROW()-ROW($A$7)+1 returns 1 A8: =ROW()-ROW($A$7)+1 returns 2 A9: =ROW()-ROW($A$7)+1 returns 3 A10: =ROW()-ROW($A$7)+1 returns 4 A11: =ROW()-ROW($A$7)+1 returns 5 A12: =ROW()-ROW($A$7)+1 returns 6 Biff's: C7: =ROWS($1:1) returns 1 C8: =ROWS($1:2) returns 2 C9: =ROWS($1:3) returns 3 C10: =ROWS($1:4) returns 4 C11: =ROWS($1:5) returns 5 C12: =ROWS($1:6) returns 6 mine: E7: =ROWS(E$7:E7) returns 1 E8: =ROWS(E$7:E8) returns 2 E9: =ROWS(E$7:E9) returns 3 E10: =ROWS(E$7:E10) returns 4 E11: =ROWS(E$7:E11) returns 5 E12: =ROWS(E$7:E12) returns 6 No differences so far. Undo that cell insertion. Now insert cells above A7:E8, that is, within these formula ranges. These formulas become Bernie's: A5: =ROW()-ROW($A$5)+1 returns 1 A6: =ROW()-ROW($A$5)+1 returns 2 A7: <blank A8: <blank A9: =ROW()-ROW($A$5)+1 returns 5 A10: =ROW()-ROW($A$5)+1 returns 6 A11: =ROW()-ROW($A$5)+1 returns 7 A12: =ROW()-ROW($A$5)+1 returns 8 Biff's: C5: =ROWS($1:1) returns 1 C6: =ROWS($1:2) returns 2 C7: <blank C8: <blank C9: =ROWS($1:3) returns 3 C10: =ROWS($1:4) returns 4 C11: =ROWS($1:5) returns 5 C12: =ROWS($1:6) returns 6 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: <blank E8: <blank E9: =ROWS(E$5:E9) returns 5 E10: =ROWS(E$5:E10) returns 6 E11: =ROWS(E$5:E11) returns 7 E12: =ROWS(E$5:E12) returns 8 Debatable whether Biff's formulas are still correct and the others wrong or vice versa, but there's no differences in the results of Bernie's and my formulas. Undo that cell insertion and change to inserting entire rows, but it'll produce the same results. So Biff's formulas can behave differently than Bernie's and mine. Bernie's and mine will behave the same with respect to cell or row insertion. However, they'll behave differently with respect to row DELETION. Bernie's: A5: =ROW()-ROW(#REF!)+1 returns #REF! A6: =ROW()-ROW(#REF!)+1 returns #REF! A7: =ROW()-ROW(#REF!)+1 returns #REF! A8: =ROW()-ROW(#REF!)+1 returns #REF! A9: =ROW()-ROW(#REF!)+1 returns #REF! Biff's: C5: =ROWS($1:2) returns 2 C6: =ROWS($1:3) returns 3 C7: =ROWS($1:4) returns 4 C8: =ROWS($1:4) returns 4 C9: =ROWS($1:5) returns 5 mine: E5: =ROWS(E$5:E5) returns 1 E6: =ROWS(E$5:E6) returns 2 E7: =ROWS(E$5:E7) returns 3 E8: =ROWS(E$5:E8) returns 4 E9: =ROWS(E$5:E9) returns 5 Bigtime differences now. So I may grant that Biff's ROWS($1:#) formula isn't as robust as Bernie's ROW()-ROW(base_cell)+1 formula, but Bernie's formula isn't as robust as my ROWS(base_cell:current_cell) formula. If you don't believe me, find an actual example of INSERTING cells/rows that would produce different results for Bernie's and my formulas. I've already provided one that shows they differ when DELETING cells/rows. Then there's the simple fact that shorter formulas with one function call are usually better (as in faster, less error-prone) than longer formulas with multiple function calls. You haven't convinced me that ROWS($1:#) is less robust than ROW()-ROW(base_cell)+1 but I do agree that ROWS(base_cell:current_cell) is better than both of the others. I *used* to use ROWS($1:#) just because it's the easiest to understand and saves a couple of keystrokes. -- Biff Microsoft Excel MVP |
#15
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consecutive numbers
Well guys I am now totally confused and need a week to unravel what you have
all suggested. I am sure I will plump with one eventually and thank you so much for your interest and time. This is in fact not for me but for a colleague and will leave him to decide! Thakns Debbie "Peo Sjoblom" wrote: It is simpler to use ROWS than using ROW the way you do since you need two row functions, one to offset any possible inserted rows on top thus you need to use a cell in the same row as the formula to "anchor" it. I always use it the same way as in Harlan's example and I find it much easier to use and as he showed it also adapts to row deletion so then we can also say it is better than using ROW -- Regards, Peo Sjoblom "Bernie Deitrick" <deitbe @ consumer dot org wrote in message ... Phippsy, As you have found, using the ROWS function is not better than using the ROW function, since inserting a new row 1 will mess up the ROWS formula, but not the one ROW()-ROW($a$5) etc that I posted. HTH, Bernie MS Excel MVP "Phippsy" wrote in message ... The last one I understand having looked what the ROWS function does however why is this better than using the ROW() function? Thanks "Harlan Grove" wrote: "T. Valko" wrote... Another one: =ROWS($1:1)*$A$4 .... Better to start with a single cell, e.g., if the formula were entered in cell X99, X99: =ROWS(X$99:X99)*$A$4 since any entries/changes anywhere in row 1 would cause your formula to recalc. |
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