Fin

I have slavishly copied the method by Dave ? using your figures. I came up
with Beta 2.296404 and alpha 6.485752 giving a weibull probability of failure
for 6.67 hours of 77%.

If you like, I'll send you my workings. peter_athertonAThotmail.com. do the
obvious with the AT.

Is it the best way? I don't know, what do you intend doing with the result.
For instance, how many widgits are produced during a run is it always the
same proportion of units produced by the hours or when there is a quick
failure has a lower number than expected been produced?

Ma


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Thank You Billy Liddel!

Please let me know if the WEIBULL Function is the right scenario I
should be using to get the correct probability rate failure of the
machine.