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What version of Excel are you using?
-- Rick (MVP - Excel) "TXDalessandros" wrote in message ... I am getting a compile erro on this CellValue = Replace(Replace(CellValue, vbCr, vbLf), vbLf & vbLf, vbLf) "Rick Rothstein" wrote: This macro should do what you want (set the data start row and data column in the indicated Const statements)... Sub SeparateAddressParts() Const DataStartRow As Long = 2 Const DataStartCol As String = "F" Dim X As Long Dim Z As Long Dim LastRow As Long Dim CellValue As String Dim Parts() As String With Worksheets("Sheet1") LastRow = .Cells(.Rows.Count, DataStartCol).End(xlUp).Row For X = DataStartRow To LastRow CellValue = .Cells(X, DataStartCol).Value If Len(Trim(CellValue)) 0 Then CellValue = Replace(Replace(CellValue, vbCr, vbLf), vbLf & vbLf, vbLf) Parts = Split(CellValue, vbLf) With .Cells(X, DataStartCol) .Value = Parts(0) Parts = Split(Parts(1), ",") For Z = 0 To 2 .Offset(0, Z + 1) = Trim(Parts(Z)) Next End With End If Next End With End Sub -- Rick (MVP - Excel) "TXDalessandros" wrote in message ... I have a extract from the web that puts the address field all in one and I need to split this by street address then city state and zip into the next 3 columns. My data looks like this when extracted. There is a Square for the implied enter after the end of the street address 1107 Hendrick Dr Suite B Carbondale, CO, 81623 Is there code that could be used to split this from say column F into F, G, H and I? Thank you Holly |
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