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To everyone how took the time my Thanks. It turns out your ideas were good,
it was me. D3 should have been F3 and for the waste of time I am sorry. I think I will step away and take a break for awhile "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... i just tried it and it worked for me. i put a date in a1, 9/20/05 i put your formula in d3 when i entered a 1 in c3, it formatted d9:f9 in green. did you put the code on the sheet1 or in a standard module? right click sheet1, choose view code and paste the code there if, i'm missing something, let me know -- Gary "Patrick Simonds" wrote in message ... It does not seem to work. There is a formula in cell D3 =IF(C3=0,IF(WEEKDAY($A$1)=2,$A$1),C3+1) which returns a number (to be more exact, it returns a date, and cell formatting returns the day number 1, 2, 3, ...15, 16 ect). The IsNumber seems to return a false because no color is applied to the cell. I tried swapping the color lines and then it would always change the cell color. "Gary Keramidas" <GKeramidasATmsn.com wrote in message ... norman: i am trying to learn about functions. i came up with this. would this work correctly? Private Sub Worksheet_SelectionChange(ByVal Target As Range) With Range("d9:f9") If Application.IsNumber(Range("d3")) Then .Interior.ColorIndex = 35 Else .Interior.ColorIndex = 0 End If End With End Sub -- Gary "Norman Jones" wrote in message ... Hi Patrick, "Patrick Simonds" wrote in message ... I need a formula which will look at cell D3, and if the formula has returned a number then execute the following code: Range("D9:F9").Select Selection.Interior.ColorIndex = 35 A formula cannot change the format of another cell. If you want to use VBA, try: '============ Public Sub aTester() Dim rng As Range Set rng = Selection With rng.Interior If Application.IsNumber(Range("D3")) Then .ColorIndex = 35 Else .ColorIndex = 0 End If End With End Sub '<<============ --- Regards, Norman |
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