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#1




A Difficult Unconcatinate Problem
Hi,
I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA 
#2




I'd use some helper columns and formulas.
Assumes your data is in A1:Axxx. In B1, put this formula: =MATCH(TRUE,ISNUMBER(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),0) This is an array formula. Hit ctrlshiftenter instead of enter. If you do it correctly, excel will wrap curly brackets {} around your formula. (don't type them yourself.) In C1, put this formula: =SEARCH("source:",A1) In D1, put this formula: =TRIM(LEFT(A1,B11)) In E1: =MID(A1,B1,C1B1) In F1: =TRIM(MID(A1,C1+LEN("source:"),255)) And select b1:F1 and drag down as far as you need. RestlessAde wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA  Dave Peterson 
#3




Well, I think I'd start with DataText to Columns then sort out those
countries with more than one word afterwards (can't be too many of them) or you can do some checking using the CODE function to find the number part of the contents and use the string functions to split up the different elements "RestlessAde" wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA 
#4




Dave,
That's fantastic. I don't understand how it works at the moment, although I shall invest some brain power into trying to understand it for future reference. Thanks for replying so quickly. Thanks also to bigwheel. RA "Dave Peterson" wrote: I'd use some helper columns and formulas. Assumes your data is in A1:Axxx. In B1, put this formula: =MATCH(TRUE,ISNUMBER(MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),0) This is an array formula. Hit ctrlshiftenter instead of enter. If you do it correctly, excel will wrap curly brackets {} around your formula. (don't type them yourself.) In C1, put this formula: =SEARCH("source:",A1) In D1, put this formula: =TRIM(LEFT(A1,B11)) In E1: =MID(A1,B1,C1B1) In F1: =TRIM(MID(A1,C1+LEN("source:"),255)) And select b1:F1 and drag down as far as you need. RestlessAde wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA  Dave Peterson 
#5




try
=MIN(IF(ISERROR(FIND({"1","2","3","4","5","6","7", "8","9","0"},B2)),1000000,FIND({"1","2","3","4","5 ","6","7","8","9","0"},B2))) to find your first number "RestlessAde" wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA 
#6




On Tue, 13 Sep 2005 05:57:13 0700, "RestlessAde"
wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA Array formulas will do this. The first two are array formulas; the last is not. To enter an array formula, be sure to hold down <ctrl<shift while hitting <enter. Excel will place braces {...} around the formula. Assuming data is in A2. Country (array formula): =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) Data Value (array formula): =MID(A2,MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0),1+FIND("Source",A2) MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0)) Source (NOT an array formula) =MID(A3,FIND("Source: ",A3)+8,255) ron 
#7




A Difficult Unconcatinate Problem
"Ron Rosenfeld" wrote:
On Tue, 13 Sep 2005 05:57:13 0700, "RestlessAde" wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA Array formulas will do this. The first two are array formulas; the last is not. To enter an array formula, be sure to hold down <ctrl<shift while hitting <enter. Excel will place braces {...} around the formula. Assuming data is in A2. Country (array formula): =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) Data Value (array formula): =MID(A2,MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0),1+FIND("Source",A2) MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0)) Source (NOT an array formula) =MID(A3,FIND("Source: ",A3)+8,255) ron Ron (or anyone else for that matter), The first array formula cited above has solved a very major headach I've been working on all day as it can be modified to give the position of the first number in a mixed string of numbers and letters and for that you deserve major kudos! However I hate not knowing how it is achieved! Can you explain in plain english how this is working? I guess this may help me get my head around a few other thorny issues I have pending and it may just help out a few others here too Thanks in advance R.Douthwaite 
#8




A Difficult Unconcatinate Problem
On Tue, 24 Jan 2006 11:27:51 0800, R.Douthwaite
wrote: "Ron Rosenfeld" wrote: On Tue, 13 Sep 2005 05:57:13 0700, "RestlessAde" wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA Array formulas will do this. The first two are array formulas; the last is not. To enter an array formula, be sure to hold down <ctrl<shift while hitting <enter. Excel will place braces {...} around the formula. Assuming data is in A2. Country (array formula): =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) Data Value (array formula): =MID(A2,MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0),1+FIND("Source",A2) MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0)) Source (NOT an array formula) =MID(A3,FIND("Source: ",A3)+8,255) ron Ron (or anyone else for that matter), The first array formula cited above has solved a very major headach I've been working on all day as it can be modified to give the position of the first number in a mixed string of numbers and letters and for that you deserve major kudos! However I hate not knowing how it is achieved! Can you explain in plain english how this is working? I guess this may help me get my head around a few other thorny issues I have pending and it may just help out a few others here too Thanks in advance R.Douthwaite =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) If you separate out the various nestings: MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1) This segment returns an array of each character in A2. (The ROW(INDIRECT(...) returns an array of "1:n" where n is the number of characters in A2. The next step is to put a minus sign < in front of each character: MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1) If the character is NOT a number, the array will return an error; otherwise it will return a number. We then Test each character position to see if there is an error: ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)) This returns an array of {TRUE,TRUE,FALSE...} depending on whether there is a digit. The MATCH function with the 0 match_type argument then finds the first FALSE which would be the location of the first digit. ================================ Since September, however, I've become enamored of "regular expressions". One way of using these effectively in Excel is to download and install Longre's morefunc.xll addin from http://xcell05.free.fr/ Then, to find the position of the first number in the above, one could use the much simpler formula: =REGEX.FIND(A1,"\d") To extract the first number, where it might contain commas: =REGEX.MID(A1,"(\d+,)+") Depending on your data, these can be much more flexible. ron 
#9




A Difficult Unconcatinate Problem
 R.Douthwaite. Information Coordinator www.swiftresearch.co.uk "Ron Rosenfeld" wrote: On Tue, 24 Jan 2006 11:27:51 0800, R.Douthwaite wrote: "Ron Rosenfeld" wrote: On Tue, 13 Sep 2005 05:57:13 0700, "RestlessAde" wrote: Hi, I have tried to solve this problem using a mixture of text functions such as RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any suggestions. I'm trying to split out the following data stored in a single column into three columns: Country, Data Value and Source. Angola 13,294,000 Source: ibid. Anguilla 13,000 Source: ibid. Antigua and Barbuda 76,000 Source: ibid. Argentina 37,880,000 Source: ibid. Armenia 3,206,000 Source: ibid. Aruba 94,000 Source: ibid. Australia 20,125,000 Source: ibid. The problem I'm having relates to the fact that some countries contain more than one word, so I can't just search for the first " ". I think the answer is to somehow detect the first instance of a numeric value, but I have no idea how to do this. Thanks, RA Array formulas will do this. The first two are array formulas; the last is not. To enter an array formula, be sure to hold down <ctrl<shift while hitting <enter. Excel will place braces {...} around the formula. Assuming data is in A2. Country (array formula): =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) Data Value (array formula): =MID(A2,MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0),1+FIND("Source",A2) MATCH(FALSE,ISERROR(MID(A2,ROW( INDIRECT("1:"&LEN(A2))),1)),0)) Source (NOT an array formula) =MID(A3,FIND("Source: ",A3)+8,255) ron Ron (or anyone else for that matter), The first array formula cited above has solved a very major headach I've been working on all day as it can be modified to give the position of the first number in a mixed string of numbers and letters and for that you deserve major kudos! However I hate not knowing how it is achieved! Can you explain in plain english how this is working? I guess this may help me get my head around a few other thorny issues I have pending and it may just help out a few others here too Thanks in advance R.Douthwaite =LEFT(A2,1+MATCH(FALSE,ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0)) If you separate out the various nestings: MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1) This segment returns an array of each character in A2. (The ROW(INDIRECT(...) returns an array of "1:n" where n is the number of characters in A2. The next step is to put a minus sign < in front of each character: MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1) If the character is NOT a number, the array will return an error; otherwise it will return a number. We then Test each character position to see if there is an error: ISERROR(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)) This returns an array of {TRUE,TRUE,FALSE...} depending on whether there is a digit. The MATCH function with the 0 match_type argument then finds the first FALSE which would be the location of the first digit. ================================ Since September, however, I've become enamored of "regular expressions". One way of using these effectively in Excel is to download and install Longre's morefunc.xll addin from http://xcell05.free.fr/ Then, to find the position of the first number in the above, one could use the much simpler formula: =REGEX.FIND(A1,"\d") To extract the first number, where it might contain commas: =REGEX.MID(A1,"(\d+,)+") Depending on your data, these can be much more flexible. ron Ron, Thank you for the excellent explaination. I think you just opened up a whole new world to me... Not sure that's necessarily a good thing :) R.Douthwaite 
#10




A Difficult Unconcatinate Problem
On Tue, 24 Jan 2006 15:39:02 0800, R.Douthwaite
wrote: Ron, Thank you for the excellent explaination. I think you just opened up a whole new world to me... Not sure that's necessarily a good thing :) R.Douthwaite You're very welcome. ron 
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