Remember Me? A Difficult Unconcatinate Problem

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

 Dave Peterson Posts: n/a I'd use some helper columns and formulas.

Assumes your data is in A1:Axxx.

In B1, put this formula:
=MATCH(TRUE,ISNUMBER(-MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),0)
This is an array formula. Hit ctrl-shift-enter instead of enter. If you do it
correctly, excel will wrap curly brackets {} around your formula. (don't type
them yourself.)

In C1, put this formula:
=SEARCH("source:",A1)

In D1, put this formula:
=TRIM(LEFT(A1,B1-1))

In E1:
=--MID(A1,B1,C1-B1)

In F1:
=TRIM(MID(A1,C1+LEN("source:"),255))

And select b1:F1 and drag down as far as you need.

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

--

Dave Peterson
 bigwheel Posts: n/a Well, I think I'd start with DataText to Columns then sort out those
countries with more than one word afterwards (can't be too many of them) or
you can do some checking using the CODE function to find the number part of
the contents and use the string functions to split up the different elements

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA Dave,

That's fantastic. I don't understand how it works at the moment, although I
shall invest some brain power into trying to understand it for future
reference. Thanks for replying so quickly.

Thanks also to bigwheel.

RA

"Dave Peterson" wrote:

I'd use some helper columns and formulas.

Assumes your data is in A1:Axxx.

In B1, put this formula:
=MATCH(TRUE,ISNUMBER(-MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),0)
This is an array formula. Hit ctrl-shift-enter instead of enter. If you do it
correctly, excel will wrap curly brackets {} around your formula. (don't type
them yourself.)

In C1, put this formula:
=SEARCH("source:",A1)

In D1, put this formula:
=TRIM(LEFT(A1,B1-1))

In E1:
=--MID(A1,B1,C1-B1)

In F1:
=TRIM(MID(A1,C1+LEN("source:"),255))

And select b1:F1 and drag down as far as you need.

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

--

Dave Peterson

 bj Posts: n/a try
=MIN(IF(ISERROR(FIND({"1","2","3","4","5","6","7", "8","9","0"},B2)),1000000,FIND({"1","2","3","4","5 ","6","7","8","9","0"},B2)))

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

 Ron Rosenfeld Posts: n/a On Tue, 13 Sep 2005 05:57:13 -0700, "RestlessAde"
wrote:

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

Array formulas will do this. The first two are array formulas; the last is
not. To enter an array formula, be sure to hold down <ctrl<shift while
hitting <enter. Excel will place braces {...} around the formula.

Assuming data is in A2.

Country (array formula):

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

Data Value (array formula):

=MID(A2,MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0),-1+FIND("Source",A2)
-MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0))

Source (NOT an array formula)

=MID(A3,FIND("Source: ",A3)+8,255)

--ron
 R.Douthwaite Posts: n/a A Difficult Unconcatinate Problem

"Ron Rosenfeld" wrote:

On Tue, 13 Sep 2005 05:57:13 -0700, "RestlessAde"
wrote:

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

Array formulas will do this. The first two are array formulas; the last is
not. To enter an array formula, be sure to hold down <ctrl<shift while
hitting <enter. Excel will place braces {...} around the formula.

Assuming data is in A2.

Country (array formula):

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

Data Value (array formula):

=MID(A2,MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0),-1+FIND("Source",A2)
-MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0))

Source (NOT an array formula)

=MID(A3,FIND("Source: ",A3)+8,255)

--ron

Ron (or anyone else for that matter),

The first array formula cited above has solved a very major headach I've
been working on all day as it can be modified to give the position of the
first number in a mixed string of numbers and letters and for that you
deserve major kudos!

However I hate not knowing how it is achieved! Can you explain in plain
english how this is working?

I guess this may help me get my head around a few other thorny issues I have
pending and it may just help out a few others here too

R.Douthwaite
 Ron Rosenfeld Posts: n/a A Difficult Unconcatinate Problem

On Tue, 24 Jan 2006 11:27:51 -0800, R.Douthwaite
wrote:

"Ron Rosenfeld" wrote:

On Tue, 13 Sep 2005 05:57:13 -0700, "RestlessAde"
wrote:

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

Array formulas will do this. The first two are array formulas; the last is
not. To enter an array formula, be sure to hold down <ctrl<shift while
hitting <enter. Excel will place braces {...} around the formula.

Assuming data is in A2.

Country (array formula):

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

Data Value (array formula):

=MID(A2,MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0),-1+FIND("Source",A2)
-MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0))

Source (NOT an array formula)

=MID(A3,FIND("Source: ",A3)+8,255)

--ron

Ron (or anyone else for that matter),

The first array formula cited above has solved a very major headach I've
been working on all day as it can be modified to give the position of the
first number in a mixed string of numbers and letters and for that you
deserve major kudos!

However I hate not knowing how it is achieved! Can you explain in plain
english how this is working?

I guess this may help me get my head around a few other thorny issues I have
pending and it may just help out a few others here too

R.Douthwaite

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

If you separate out the various nestings:

MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)

This segment returns an array of each character in A2. (The ROW(INDIRECT(...)
returns an array of "1:n" where n is the number of characters in A2.

The next step is to put a minus sign <- in front of each character:

-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)

If the character is NOT a number, the array will return an error; otherwise it
will return a number.

We then Test each character position to see if there is an error:

ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1))

This returns an array of {TRUE,TRUE,FALSE...} depending on whether there is a
digit.

The MATCH function with the 0 match_type argument then finds the first FALSE
which would be the location of the first digit.

================================

Since September, however, I've become enamored of "regular expressions". One
way of using these effectively in Excel is to download and install Longre's

Then, to find the position of the first number in the above, one could use the
much simpler formula:

=REGEX.FIND(A1,"\d")

To extract the first number, where it might contain commas:

=REGEX.MID(A1,"(\d+|,)+")

Depending on your data, these can be much more flexible.

--ron
 R.Douthwaite Posts: n/a A Difficult Unconcatinate Problem

--
R.Douthwaite.
Information Coordinator
www.swift-research.co.uk

"Ron Rosenfeld" wrote:

On Tue, 24 Jan 2006 11:27:51 -0800, R.Douthwaite
wrote:

"Ron Rosenfeld" wrote:

On Tue, 13 Sep 2005 05:57:13 -0700, "RestlessAde"
wrote:

Hi,

I have tried to solve this problem using a mixture of text functions such as
RIGHT, LEN, LEFT, FIND etc. However, am still stuck. Would appreciate any
suggestions.

I'm trying to split out the following data stored in a single column into
three columns: Country, Data Value and Source.

Angola 13,294,000 Source: ibid.
Anguilla 13,000 Source: ibid.
Antigua and Barbuda 76,000 Source: ibid.
Argentina 37,880,000 Source: ibid.
Armenia 3,206,000 Source: ibid.
Aruba 94,000 Source: ibid.
Australia 20,125,000 Source: ibid.

The problem I'm having relates to the fact that some countries contain more
than one word, so I can't just search for the first " ". I think the answer
is to somehow detect the first instance of a numeric value, but I have no
idea how to do this.

Thanks,
RA

Array formulas will do this. The first two are array formulas; the last is
not. To enter an array formula, be sure to hold down <ctrl<shift while
hitting <enter. Excel will place braces {...} around the formula.

Assuming data is in A2.

Country (array formula):

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

Data Value (array formula):

=MID(A2,MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0),-1+FIND("Source",A2)
-MATCH(FALSE,ISERROR(-MID(A2,ROW(
INDIRECT("1:"&LEN(A2))),1)),0))

Source (NOT an array formula)

=MID(A3,FIND("Source: ",A3)+8,255)

--ron

Ron (or anyone else for that matter),

The first array formula cited above has solved a very major headach I've
been working on all day as it can be modified to give the position of the
first number in a mixed string of numbers and letters and for that you
deserve major kudos!

However I hate not knowing how it is achieved! Can you explain in plain
english how this is working?

I guess this may help me get my head around a few other thorny issues I have
pending and it may just help out a few others here too

R.Douthwaite

=LEFT(A2,-1+MATCH(FALSE,ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)),0))

If you separate out the various nestings:

MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)

This segment returns an array of each character in A2. (The ROW(INDIRECT(...)
returns an array of "1:n" where n is the number of characters in A2.

The next step is to put a minus sign <- in front of each character:

-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)

If the character is NOT a number, the array will return an error; otherwise it
will return a number.

We then Test each character position to see if there is an error:

ISERROR(-MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1))

This returns an array of {TRUE,TRUE,FALSE...} depending on whether there is a
digit.

The MATCH function with the 0 match_type argument then finds the first FALSE
which would be the location of the first digit.

================================

Since September, however, I've become enamored of "regular expressions". One
way of using these effectively in Excel is to download and install Longre's

Then, to find the position of the first number in the above, one could use the
much simpler formula:

=REGEX.FIND(A1,"\d")

To extract the first number, where it might contain commas:

=REGEX.MID(A1,"(\d+|,)+")

Depending on your data, these can be much more flexible.

--ron

Ron,

Thank you for the excellent explaination. I think you just opened up a whole
new world to me... Not sure that's necessarily a good thing :-)

R.Douthwaite
 Ron Rosenfeld Posts: n/a A Difficult Unconcatinate Problem

On Tue, 24 Jan 2006 15:39:02 -0800, R.Douthwaite
wrote:

Ron,

Thank you for the excellent explaination. I think you just opened up a whole
new world to me... Not sure that's necessarily a good thing :-)

R.Douthwaite

You're very welcome.
--ron

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