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Conditional Formatting
I have some conditional formatting in column J on my worksheet that checks if it is less than the value in column C. If so, the font color is red. However, column C can also be blank sometimes and if I put a value in column J, then it displays it in red font color, which I don't want. Is there a way to add something to the conditional formatting which will only display column J in red font if it is less than column C and column C is not blank? -- LAF ------------------------------------------------------------------------ LAF's Profile: http://www.excelforum.com/member.php...fo&userid=9656 View this thread: http://www.excelforum.com/showthread...hreadid=466060 |
#2
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LAF try =AND(C2<"",C2J2) HTH -- Casey ------------------------------------------------------------------------ Casey's Profile: http://www.excelforum.com/member.php...fo&userid=4545 View this thread: http://www.excelforum.com/showthread...hreadid=466060 |
#3
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LAF
The only way I could reproduce your situation was by inserting a space in Col C. You might want to check to see if there are spaces and nullify them, or rewrite the conditional format with a second criteria (as criteria #1) to read: Formula Is =$C$1 (and set the font to Black). Again this has to be the first criteria. Conditional Formatting can have 3 criteria, but will stops when it reaches the first True occurrance. -- Regards... "LAF" wrote: I have some conditional formatting in column J on my worksheet that checks if it is less than the value in column C. If so, the font color is red. However, column C can also be blank sometimes and if I put a value in column J, then it displays it in red font color, which I don't want. Is there a way to add something to the conditional formatting which will only display column J in red font if it is less than column C and column C is not blank? -- LAF ------------------------------------------------------------------------ LAF's Profile: http://www.excelforum.com/member.php...fo&userid=9656 View this thread: http://www.excelforum.com/showthread...hreadid=466060 |
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