I'm trying to display 16 digit numbers in excel but it keeps converting the
last digit to a zero. Is there a way to format the cells so the 16 digits are
displayed and can be used in a vlookup formula ?

On Wed, 30 Mar 2005 01:55:02 -0800, CiaraF
wrote:

I'm trying to display 16 digit numbers in excel but it keeps converting the
last digit to a zero. Is there a way to format the cells so the 16 digits are
displayed and can be used in a vlookup formula ?

Excel (and most spreadsheet) specifications are in accord with an IEEE standard
which has a 15 digit precision.

The only way to do what you want is to enter the value as TEXT. Either precede
your entry with an apostrophe (which will not be displayed; OR format the cell
as TEXT prior to making your entry.

VLOOKUP will work with TEXT entries.
--ron

Ron Rosenfeld wrote:

....
Excel (and most spreadsheet) specifications are in accord with an IEEE standard
which has a 15 digit precision.
....


FYI Many IEEE double precision packages will display more than 15 digits
(for instance, R and S-PLUS display 17). Most 16 digit numbers,
including integers up to
2^53-1 = 9007199254740991
are exactly representable. Presumably MS chose to limit display to 15
digits to avoid questions when unrepresentable 16 digit numbers, such as
2^53+1 = 9007199254740993
get changed to different 16 digit numbers (9007199254740992) that are
representable.

This also relates to a difference between Excel and VBA. If you past a
16+ digit number into Excel, the number will be truncated (not rounded)
to 15 digits before conversion to binary. If you paste a 16+ digit
number into into VBA, that number will be converted to binary directly
(the trailing digits will impact the binary representation), although
subsequent editing of that line would then obliterate the original extra
precision. The easiest way to see this phenomenon is to compare the
result of the Excel formula
=("2059510000000001"-"2059510000000000")
with the result of the VBA formula
dif = CDbl("2059510000000001") - CDbl("2059510000000000")

You can use VBA to poke better representations of 16+ digit numbers into
Excel cells.

It would be nice if future versions of Excel would do the binary
conversion without truncation (like VBA), but I'm not holding my breath ...

Jerry

On Wed, 30 Mar 2005 08:02:02 -0500, "Jerry W. Lewis"
wrote:

Ron Rosenfeld wrote:

...
Excel (and most spreadsheet) specifications are in accord with an IEEE standard
which has a 15 digit precision.
...


FYI Many IEEE double precision packages will display more than 15 digits
(for instance, R and S-PLUS display 17). Most 16 digit numbers,
including integers up to
2^53-1 = 9007199254740991
are exactly representable. Presumably MS chose to limit display to 15
digits to avoid questions when unrepresentable 16 digit numbers, such as
2^53+1 = 9007199254740993
get changed to different 16 digit numbers (9007199254740992) that are
representable.

This also relates to a difference between Excel and VBA. If you past a
16+ digit number into Excel, the number will be truncated (not rounded)
to 15 digits before conversion to binary. If you paste a 16+ digit
number into into VBA, that number will be converted to binary directly
(the trailing digits will impact the binary representation), although
subsequent editing of that line would then obliterate the original extra
precision. The easiest way to see this phenomenon is to compare the
result of the Excel formula
=("2059510000000001"-"2059510000000000")
with the result of the VBA formula
dif = CDbl("2059510000000001") - CDbl("2059510000000000")

You can use VBA to poke better representations of 16+ digit numbers into
Excel cells.

It would be nice if future versions of Excel would do the binary
conversion without truncation (like VBA), but I'm not holding my breath ...

Jerry

Thank you for that explanation.


--ron