Thanks Biff, that worked great. I appreciate your time on this.

KJ

"T. Valko" wrote:

Hmmm...

Well, let's start with this and go from there.

This will average the last 5 numbers in the range A1:J1.

Array entered** :

=AVERAGE(J1:INDEX(A1:J1,LARGE(IF(ISNUMBER(A1:J1),C OLUMN(A1:J1)-MIN(COLUMN(A1:J1))+1),5)))

If there are less than 5 numbers the formula will return a #NUM! error.

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER)

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hey there. If there are only 5 numbers at some point, the 5 and 10 would
be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there
will
be somewhere around 30 numbers out of 40 potential leaving 10 random
spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks

"T. Valko" wrote:

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last
10
numbers in a row of up to 40 numbers. There will be various random
spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have
a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks