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Default Complex Averages

Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers spread
over 40 rows, I would need to average the last 5 which could each have a few
spaces between them. There will be no 0's or negatives in the data.

Thanks
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Default Complex Averages

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks



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Posts: 5
Default Complex Averages

Hey there. If there are only 5 numbers at some point, the 5 and 10 would be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there will
be somewhere around 30 numbers out of 40 potential leaving 10 random spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks

"T. Valko" wrote:

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks




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Default Complex Averages

But if you are putting numbers into random cells in the range, how
would you know which were the last 5 or last 10 entered? Do you not
mean last by date of entry, but rather last in the sequence of data?

Pete

On Sep 25, 9:32 pm, kjal wrote:
Hey there. If there are only 5 numbers at some point, the 5 and 10 would be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there will
be somewhere around 30 numbers out of 40 potential leaving 10 random spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks



"T. Valko" wrote:
What should happen if there aren't 5 or 10 numbers to average?


--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have a
few
spaces between them. There will be no 0's or negatives in the data.


Thanks- Hide quoted text -


- Show quoted text -



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Default Complex Averages

Maybe I am not explaining well or maybe it is not possible to average the
last 5 or whatever numbers of a list of numbers that has spaces but no zeros.
The range in the avg formula will be c2:c42, and the numbers will ultimatley
fill 3/4 of the fields with random spaces for the balance, So the formula,
hopefully, will avg the last 5 NUMBERS in the row, ignoring the spaces. So
the numbers in the avg of the last 5 may be spread over 7 or 8 spaces.

"Pete_UK" wrote:

But if you are putting numbers into random cells in the range, how
would you know which were the last 5 or last 10 entered? Do you not
mean last by date of entry, but rather last in the sequence of data?

Pete

On Sep 25, 9:32 pm, kjal wrote:
Hey there. If there are only 5 numbers at some point, the 5 and 10 would be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there will
be somewhere around 30 numbers out of 40 potential leaving 10 random spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks



"T. Valko" wrote:
What should happen if there aren't 5 or 10 numbers to average?


--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have a
few
spaces between them. There will be no 0's or negatives in the data.


Thanks- Hide quoted text -


- Show quoted text -






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Posts: 15,768
Default Complex Averages

Try this array formula** :

=AVERAGE(C42:INDEX(C2:C42,LARGE(IF(ISNUMBER(C2:C42 ),ROW(C2:C42)-MIN(ROW(C2:C42))+1),5)))

If there are less than 5 numbers the formula will return a #NUM! error.

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER)

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Maybe I am not explaining well or maybe it is not possible to average the
last 5 or whatever numbers of a list of numbers that has spaces but no
zeros.
The range in the avg formula will be c2:c42, and the numbers will
ultimatley
fill 3/4 of the fields with random spaces for the balance, So the formula,
hopefully, will avg the last 5 NUMBERS in the row, ignoring the spaces. So
the numbers in the avg of the last 5 may be spread over 7 or 8 spaces.

"Pete_UK" wrote:

But if you are putting numbers into random cells in the range, how
would you know which were the last 5 or last 10 entered? Do you not
mean last by date of entry, but rather last in the sequence of data?

Pete

On Sep 25, 9:32 pm, kjal wrote:
Hey there. If there are only 5 numbers at some point, the 5 and 10
would be
the same. I hope that helps. Basically, over the course of 3 or so
months,
these numbers will begin to be added to the rows and by the end, there
will
be somewhere around 30 numbers out of 40 potential leaving 10 random
spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks



"T. Valko" wrote:
What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP

"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and
last 10
numbers in a row of up to 40 numbers. There will be various random
spaces
between the entered numbers. So for example, if there are 15
numbers
spread
over 40 rows, I would need to average the last 5 which could each
have a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks- Hide quoted text -

- Show quoted text -






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Default Complex Averages

So, I can now see that you are talking about a column of data - in
your first post you said the numbers were in a row !!

When you talk about "spaces" do you really mean just empty cells, or
will there be a <space in those cells? Some people use a <space to
"delete" an entry.

Pete

On Sep 25, 10:02 pm, kjal wrote:
Maybe I am not explaining well or maybe it is not possible to average the
last 5 or whatever numbers of a list of numbers that has spaces but no zeros.
The range in the avg formula will be c2:c42, and the numbers will ultimatley
fill 3/4 of the fields with random spaces for the balance, So the formula,
hopefully, will avg the last 5 NUMBERS in the row, ignoring the spaces. So
the numbers in the avg of the last 5 may be spread over 7 or 8 spaces.



"Pete_UK" wrote:
But if you are putting numbers into random cells in the range, how
would you know which were the last 5 or last 10 entered? Do you not
mean last by date of entry, but rather last in the sequence of data?


Pete


On Sep 25, 9:32 pm, kjal wrote:
Hey there. If there are only 5 numbers at some point, the 5 and 10 would be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there will
be somewhere around 30 numbers out of 40 potential leaving 10 random spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.


Thanks


"T. Valko" wrote:
What should happen if there aren't 5 or 10 numbers to average?


--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last 10
numbers in a row of up to 40 numbers. There will be various random spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have a
few
spaces between them. There will be no 0's or negatives in the data.


Thanks- Hide quoted text -


- Show quoted text -- Hide quoted text -


- Show quoted text -



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Posts: 15,768
Default Complex Averages

Hmmm...

Well, let's start with this and go from there.

This will average the last 5 numbers in the range A1:J1.

Array entered** :

=AVERAGE(J1:INDEX(A1:J1,LARGE(IF(ISNUMBER(A1:J1),C OLUMN(A1:J1)-MIN(COLUMN(A1:J1))+1),5)))

If there are less than 5 numbers the formula will return a #NUM! error.

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER)

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hey there. If there are only 5 numbers at some point, the 5 and 10 would
be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there
will
be somewhere around 30 numbers out of 40 potential leaving 10 random
spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks

"T. Valko" wrote:

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last
10
numbers in a row of up to 40 numbers. There will be various random
spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have
a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks






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Posts: 5
Default Complex Averages

Thanks Biff, that worked great. I appreciate your time on this.

KJ

"T. Valko" wrote:

Hmmm...

Well, let's start with this and go from there.

This will average the last 5 numbers in the range A1:J1.

Array entered** :

=AVERAGE(J1:INDEX(A1:J1,LARGE(IF(ISNUMBER(A1:J1),C OLUMN(A1:J1)-MIN(COLUMN(A1:J1))+1),5)))

If there are less than 5 numbers the formula will return a #NUM! error.

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER)

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hey there. If there are only 5 numbers at some point, the 5 and 10 would
be
the same. I hope that helps. Basically, over the course of 3 or so months,
these numbers will begin to be added to the rows and by the end, there
will
be somewhere around 30 numbers out of 40 potential leaving 10 random
spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks

"T. Valko" wrote:

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and last
10
numbers in a row of up to 40 numbers. There will be various random
spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each have
a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks






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Posts: 15,768
Default Complex Averages

You're welcome. Thanks for the feedback!

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Thanks Biff, that worked great. I appreciate your time on this.

KJ

"T. Valko" wrote:

Hmmm...

Well, let's start with this and go from there.

This will average the last 5 numbers in the range A1:J1.

Array entered** :

=AVERAGE(J1:INDEX(A1:J1,LARGE(IF(ISNUMBER(A1:J1),C OLUMN(A1:J1)-MIN(COLUMN(A1:J1))+1),5)))

If there are less than 5 numbers the formula will return a #NUM! error.

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER)

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hey there. If there are only 5 numbers at some point, the 5 and 10
would
be
the same. I hope that helps. Basically, over the course of 3 or so
months,
these numbers will begin to be added to the rows and by the end, there
will
be somewhere around 30 numbers out of 40 potential leaving 10 random
spaces
in each column assuming 40 max. So the last 5 and last 10 averages will
develop and deviate as more data is entered.

Thanks

"T. Valko" wrote:

What should happen if there aren't 5 or 10 numbers to average?

--
Biff
Microsoft Excel MVP


"kjal" wrote in message
...
Hello, I need to design a spreadsheet that averages the last 5 and
last
10
numbers in a row of up to 40 numbers. There will be various random
spaces
between the entered numbers. So for example, if there are 15 numbers
spread
over 40 rows, I would need to average the last 5 which could each
have
a
few
spaces between them. There will be no 0's or negatives in the data.

Thanks










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