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I have a Command Button on a worksheet that I only want to display if a
specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#2
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Try this
If Environ("UserName") = "???" Then ActiveSheet.Shapes("CommandButton1").Visible = True Else ActiveSheet.Shapes("CommandButton1").Visible = False End If -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Doctorjones_md" wrote in message ... I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#3
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Change ActiveSheet to your sheet name
Sheets("???") -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Ron de Bruin" wrote in message ... Try this If Environ("UserName") = "???" Then ActiveSheet.Shapes("CommandButton1").Visible = True Else ActiveSheet.Shapes("CommandButton1").Visible = False End If -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Doctorjones_md" wrote in message ... I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#4
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Sub Auto_Open()
Dim sUserName as String sUserName = GetUserName() With worksheets("Sheet1") If lcase(sUserName) = lcase("Person's UserName") then .OleObjects("cmdQC").visible.True else .OleObjects("cmdQc").Visible = False End it End With End Sub assuming cmdQc is the name of the control -- regards, Tom Ogilvy "Doctorjones_md" wrote: I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#5
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Ron,
I tried your code -- is this supposed to be in a module, or in the code for the worksheet? Is it something like this ... Private Sub QC() If Environ("UserName") = "???" Then ActiveSheet.MySheet("cmd").Visible = True Else ActiveSheet.MySheet("CommandButton1").Visible = False End If End Sub ================================================== ====== "Ron de Bruin" wrote in message ... Try this If Environ("UserName") = "???" Then ActiveSheet.Shapes("CommandButton1").Visible = True Else ActiveSheet.Shapes("CommandButton1").Visible = False End If -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Doctorjones_md" wrote in message ... I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#6
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In your example you use
Sub Auto_Open() You must copy this in a normal module See http://www.cpearson.com/excel/events.htm Use this for user "ron" with the button on "Sheet1" It will run automatic if you open the workbook Sub Auto_Open() If Environ("UserName") = "Ron" Then Sheets("Sheet1").Shapes("CommandButton1").Visible = True Else Sheets("Sheet1").Shapes("CommandButton1").Visible = False End If End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Doctorjones_md" wrote in message ... Ron, I tried your code -- is this supposed to be in a module, or in the code for the worksheet? Is it something like this ... Private Sub QC() If Environ("UserName") = "???" Then ActiveSheet.MySheet("cmd").Visible = True Else ActiveSheet.MySheet("CommandButton1").Visible = False End If End Sub ================================================== ====== "Ron de Bruin" wrote in message ... Try this If Environ("UserName") = "???" Then ActiveSheet.Shapes("CommandButton1").Visible = True Else ActiveSheet.Shapes("CommandButton1").Visible = False End If -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Doctorjones_md" wrote in message ... I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
#7
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Tom,
My apologies for not posting back sooner -- the code you provided did the trick PERFECTLY! Thanks a bunch -- have an awesome weekend. Shane ============= "Tom Ogilvy" wrote in message ... Sub Auto_Open() Dim sUserName as String sUserName = GetUserName() With worksheets("Sheet1") If lcase(sUserName) = lcase("Person's UserName") then .OleObjects("cmdQC").visible.True else .OleObjects("cmdQc").Visible = False End it End With End Sub assuming cmdQc is the name of the control -- regards, Tom Ogilvy "Doctorjones_md" wrote: I have a Command Button on a worksheet that I only want to display if a specified User Opens the workbook. I have the following code: (in a UserName module) ================= ' By Chris Rae, 14/6/99, 3/9/00. Option Explicit ' This is used by GetUserName() to find the current user's ' name from the API Declare Function Get_User_Name Lib "advapi32.dll" Alias _ "GetUserNameA" (ByVal lpBuffer As String, _ nSize As Long) As Long Function GetUserName() As String Dim lpBuff As String * 25 Dim txtName As String Get_User_Name lpBuff, 25 GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) txtName = lpBuff MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly End Function ==================== How would I modify the code to enable the cmdQC button? I was thinking something like the following ... (In the code for the worksheet) Sub Auto_Open() GetUserName If lpBuff = 'Person's UserName' then cmdQC.visible.True End Sub Many thanks (in advance) for your assistance. Shane |
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