Tom,

My apologies for not posting back sooner -- the code you provided did the
trick PERFECTLY! Thanks a bunch -- have an awesome weekend.

Shane
=============
"Tom Ogilvy" wrote in message
...
Sub Auto_Open()
Dim sUserName as String
sUserName = GetUserName()
With worksheets("Sheet1")
If lcase(sUserName) = lcase("Person's UserName") then
.OleObjects("cmdQC").visible.True
else
.OleObjects("cmdQc").Visible = False
End it
End With
End Sub

assuming cmdQc is the name of the control

--
regards,
Tom Ogilvy


"Doctorjones_md" wrote:

I have a Command Button on a worksheet that I only want to display if a
specified User Opens the workbook.

I have the following code:

(in a UserName module)
=================
' By Chris Rae, 14/6/99, 3/9/00.
Option Explicit
' This is used by GetUserName() to find the current user's
' name from the API
Declare Function Get_User_Name Lib "advapi32.dll" Alias _
"GetUserNameA" (ByVal lpBuffer As String, _
nSize As Long) As Long
Function GetUserName() As String
Dim lpBuff As String * 25
Dim txtName As String

Get_User_Name lpBuff, 25
GetUserName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1)
txtName = lpBuff
MsgBox ("Welcome to the NEW Pricing Tool " & (lpBuff)), vbOKOnly


End Function

====================
How would I modify the code to enable the cmdQC button? I was thinking
something like the following ...

(In the code for the worksheet)
Sub Auto_Open()
GetUserName
If lpBuff = 'Person's UserName' then cmdQC.visible.True

End Sub

Many thanks (in advance) for your assistance.

Shane