Home |
Search |
Today's Posts |
#1
Posted to microsoft.public.excel.misc
|
|||
|
|||
Multiplying seconds by cost
I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating archive costs so I need to know what the amount of archive is by subtracting the end time code from the beginning, and then multiplying by the cost per second. Thanks, Monique |
#2
Posted to microsoft.public.excel.misc
|
|||
|
|||
Multiplying seconds by cost
If the time difference is in A1 and the cost per second is in B1, then:
=A1*24*60*60*B1 will convert into integer seconds and then apply the cost. -- Gary's Student gsnu200708 "MoniqueT" wrote: I would like to work out a formula to multiply the result of an equation (10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating archive costs so I need to know what the amount of archive is by subtracting the end time code from the beginning, and then multiplying by the cost per second. Thanks, Monique |
#3
Posted to microsoft.public.excel.misc
|
|||
|
|||
Multiplying seconds by cost
If your times really are in XL times like 10:00:30 then try:
=(B1-A1)*24*60*60*F1 where the rate is in F1 or by doing the multiplication: =(B1-A1)*86400*F1 -- HTH Sandy In Perth, the ancient capital of Scotland and the crowning place of kings with @tiscali.co.uk "MoniqueT" wrote in message ... I would like to work out a formula to multiply the result of an equation (10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating archive costs so I need to know what the amount of archive is by subtracting the end time code from the beginning, and then multiplying by the cost per second. Thanks, Monique |
#4
Posted to microsoft.public.excel.misc
|
|||
|
|||
Multiplying seconds by cost
Thank you VERY very much. That's fantastic.
"MoniqueT" wrote: I would like to work out a formula to multiply the result of an equation (10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating archive costs so I need to know what the amount of archive is by subtracting the end time code from the beginning, and then multiplying by the cost per second. Thanks, Monique |
#5
Posted to microsoft.public.excel.misc
|
|||
|
|||
Multiplying seconds by cost
Thanks Sandy.
"Sandy Mann" wrote: If your times really are in XL times like 10:00:30 then try: =(B1-A1)*24*60*60*F1 where the rate is in F1 or by doing the multiplication: =(B1-A1)*86400*F1 -- HTH Sandy In Perth, the ancient capital of Scotland and the crowning place of kings with @tiscali.co.uk "MoniqueT" wrote in message ... I would like to work out a formula to multiply the result of an equation (10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating archive costs so I need to know what the amount of archive is by subtracting the end time code from the beginning, and then multiplying by the cost per second. Thanks, Monique |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
Calculate call cost in seconds | Excel Worksheet Functions | |||
Converting Julian Seconds with a macro to replace old seconds data | Excel Discussion (Misc queries) | |||
Current Cost versus Original Cost | New Users to Excel | |||
Confusion on adding percentage of cost to that cost. | Excel Worksheet Functions | |||
Convert "Time Interval" in "hours : minutes : seconds" to seconds | New Users to Excel |