Multiplying seconds by cost
 

I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating
archive costs so I need to know what the amount of archive is by subtracting
the end time code from the beginning, and then multiplying by the cost per
second.

Thanks,

Monique

Multiplying seconds by cost
 

If the time difference is in A1 and the cost per second is in B1, then:

=A1*24*60*60*B1

will convert into integer seconds and then apply the cost.
--
Gary's Student
gsnu200708


"MoniqueT" wrote:

I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating
archive costs so I need to know what the amount of archive is by subtracting
the end time code from the beginning, and then multiplying by the cost per
second.

Thanks,

Monique

Multiplying seconds by cost
 

If your times really are in XL times like 10:00:30 then try:

=(B1-A1)*24*60*60*F1
where the rate is in F1

or by doing the multiplication:

=(B1-A1)*86400*F1


--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


with @tiscali.co.uk


"MoniqueT" wrote in message
...
I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating
archive costs so I need to know what the amount of archive is by
subtracting
the end time code from the beginning, and then multiplying by the cost per
second.

Thanks,

Monique

Multiplying seconds by cost
 

Thank you VERY very much. That's fantastic.

"MoniqueT" wrote:

I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating
archive costs so I need to know what the amount of archive is by subtracting
the end time code from the beginning, and then multiplying by the cost per
second.

Thanks,

Monique

Multiplying seconds by cost
 

Thanks Sandy.

"Sandy Mann" wrote:

If your times really are in XL times like 10:00:30 then try:

=(B1-A1)*24*60*60*F1
where the rate is in F1

or by doing the multiplication:

=(B1-A1)*86400*F1


--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


with @tiscali.co.uk


"MoniqueT" wrote in message
...
I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am calculating
archive costs so I need to know what the amount of archive is by
subtracting
the end time code from the beginning, and then multiplying by the cost per
second.

Thanks,

Monique

Multiplying seconds by cost
 

You're welcome. I forgot to say to format the cell to currency or whatever
format you want but I guess you have found that out already <g

--
Regards,

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


with @tiscali.co.uk


"MoniqueT" wrote in message
...
Thanks Sandy.

"Sandy Mann" wrote:

If your times really are in XL times like 10:00:30 then try:

=(B1-A1)*24*60*60*F1
where the rate is in F1

or by doing the multiplication:

=(B1-A1)*86400*F1


--
HTH

Sandy
In Perth, the ancient capital of Scotland
and the crowning place of kings


with @tiscali.co.uk


"MoniqueT" wrote in message
...
I would like to work out a formula to multiply the result of an equation
(10.00.30 - 10.00.00 in hh:mm:ss) by an amount of money. I am
calculating
archive costs so I need to know what the amount of archive is by
subtracting
the end time code from the beginning, and then multiplying by the cost
per
second.

Thanks,

Monique