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![]() I think I have the answer I think the following function calculation would work.... if a1 contains 18911, 18801, 18825, 18482, 18941 then the following could give me the number of values in the cell =LEN(A1)-LEN(SUBSTITUTE(A1,",",""))+1 -- Sandih ------------------------------------------------------------------------ Sandih's Profile: http://www.excelforum.com/member.php...o&userid=36225 View this thread: http://www.excelforum.com/showthread...hreadid=560150 |
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