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Bob,
You're right again. In my data, row 1 contains a header. Your formula includes that in the count, thereby dividing by 3 instead of 2. The other formula I found uses SUM and COUNT which both ignore the text in the header. I can make yours work by subtracting 1 at the appropriate spot. Thanks for the help today. "Bob Phillips" wrote: Jim, Mine comes to 112.5 with your test data - honest! Bob "JBoulton" wrote in message ... Bob, As it turns out, that formula produces 75 with the test data - so it's not what I was looking for after all... "Bob Phillips" wrote: Jim, I get it now. Try this as an alternative =SUM(C1:C100)/SUMPRODUCT((A1:A100<"")/COUNTIF(A1:A100,A1:A100&"")) -- HTH RP (remove nothere from the email address if mailing direct) "JBoulton" wrote in message ... Bob, Here's the data again: 1/1/05 50 1/1/05 100 1/2/05 75 The total for 1/1/05 is 150 (50 + 100) and the total for 1/2/05 is 75 so the average for the two days is 112.50. If this was three batches of checks, I'd say I spent an average of 112.50 per day. I *have* discovered a solution on this board. This formula works: =SUM(C:C)/COUNT(1/FREQUENCY(A:A,A:A)) Jim "Bob Phillips" wrote: Jim, Sorry, I am lost. I assumed you had made a typo. I don't understand where the average is 112.5. 225/3 is 75, The average for the 1st is also 75. Where does 112.5 come from, or more to the point, how? -- HTH RP (remove nothere from the email address if mailing direct) "JBoulton" wrote in message ... Bob, That will certainly give me the average for any one day. What I want is the average for all the days, whether I have one item in a day or many items on the same day. This data accumulates constantly. I need the daily average. In the first example, I'm looking for a way to calculate 112.50 (225/2) not 75 (225/3). Jim "Bob Phillips" wrote: Jim, How about =SUMPRODUCT(--(A1:A20=--"2005-01-01"),C1:C20)/COUNTIF(A1:A20,--"2005-01-01") or =SUMPRODUCT(--(A1:A2000=H1),C1:C2000)/COUNTIF(A1:A200,H1) if the comparison date is in H1 -- HTH RP (remove nothere from the email address if mailing direct) "JBoulton" wrote in message ... Bernard, I *could* use a pivot table to total by day and then get an average, but by the end of the year that would be a very long table. I'm hoping that someone has a single function solution. Jim "Bernard Liengme" wrote: Sounds like a candidate for PIVOT Table. Read Help and come back with questions. best wishes -- Bernard V Liengme www.stfx.ca/people/bliengme remove caps from email "JBoulton" wrote in message ... I need a little help on a calculation. Col A contains dates, Col C contains amounts. I need to calculate an average by day given that there can be multiple entries for each day. 1/1/05 50 1/1/05 100 1/2/05 75 The calc should produce 112.50 TIA -- Jim |
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