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count # of instances in cell (a b a) answer 2 formula if possi
Great, that worked perfect. Thanks to everyone
"Bob Phillips" wrote: Sorry, I meant =SUMPRODUCT((LEN(A1:A10)-LEN(SUBSTITUTE(LOWER(A1:A10),LOWER("a"),"")))/LEN(" a")) -- HTH Bob Phillips (replace xxxx in the email address with gmail if mailing direct) "eric" wrote in message ... Thanks that worked. Is there a way to get a total for a range of cells with the formula below? "Dave Peterson" wrote: =(LEN(A1)-LEN(SUBSTITUTE(LOWER(A1),lower("a"),"")))/LEN("a") Will count the number of A's or a's in A1. If you want just the lower case a's: =(LEN(A1)-LEN(SUBSTITUTE(A1,"a","")))/LEN("a") eric wrote: I can't get the count of the number of intances of a value to work. ex: In single cell (a b a) answer=2 for "a", but does not work with any formula I have tried. =countif(data, "*"&text&"*") brings an answer of 0. I was wondering if anyone knows how or if it is possbile to do this. -- Dave Peterson |
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