vlookup e.g.

Line 1 (Table)(Col A)REF123(ColB)245
Line 2 (Table)(Col A)REF123(ColB)246
Line 3 (Table)(Col A)REF123(ColB)247 and so on..

On column C(above) i need to return column b from the array.(below)

Line 1 (Array)(Col A)REF122(ColB)243
Line 2 (Array)(Col A)REF123(ColB)244
Line 3 (Array)(Col A)REF123(ColB)245

when i do a vlookup i have to use column A for the data but when i ask for
column b to be returned it dosent match (Line 1 on Table pulls through line 2
on array when i need line 3 which is the correct match.

Is it possible to do this?

How would it know, it returns the first match.

--
HTH

Bob Phillips

(remove xxx from email address if mailing direct)

"D7ONO" wrote in message
...
vlookup e.g.

Line 1 (Table)(Col A)REF123(ColB)245
Line 2 (Table)(Col A)REF123(ColB)246
Line 3 (Table)(Col A)REF123(ColB)247 and so on..

On column C(above) i need to return column b from the array.(below)

Line 1 (Array)(Col A)REF122(ColB)243
Line 2 (Array)(Col A)REF123(ColB)244
Line 3 (Array)(Col A)REF123(ColB)245

when i do a vlookup i have to use column A for the data but when i ask for
column b to be returned it dosent match (Line 1 on Table pulls through
line 2
on array when i need line 3 which is the correct match.

Is it possible to do this?

Hi,
As Bob has said, vlookup isn't that smart - & I may be slightly off
track here, but why is line 3 the correct match?
If it's b/c this row (ie column A value & column B value) is identical
in both the table & the array, what is the point of returning column B
(of array) in column C of the Table (you could just type"=B1")?

If your intention is to return a value from an identical row you need
to use a concatenated helper column (eg, cell C1 contains "=A1&"%"&B1")
for your lookup/matching or a sum product formula.

Rob Brockett
NZ
Always learning & the best way to learn is to experience...


--
broro183
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with the data i have i firstly have to do the lookup by using column a to
match the data however columns b also have to match as they can be different
which is why line 3 is correct (colB is 245 on both sheets) whereas line 2 on
the array column b is 244 this is why i need a formula to search on column b
after the initial lookup.

hope this makes sense

"broro183" wrote:


Hi,
As Bob has said, vlookup isn't that smart - & I may be slightly off
track here, but why is line 3 the correct match?
If it's b/c this row (ie column A value & column B value) is identical
in both the table & the array, what is the point of returning column B
(of array) in column C of the Table (you could just type"=B1")?

If your intention is to return a value from an identical row you need
to use a concatenated helper column (eg, cell C1 contains "=A1&"%"&B1")
for your lookup/matching or a sum product formula.

Rob Brockett
NZ
Always learning & the best way to learn is to experience...


--
broro183
------------------------------------------------------------------------
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Seems odd that you want to find a value that you already have?

=INDEX(Table!B1:B100,MATCH(1,(Table!A1:A100=Array! A1)*(Table(B1:B100=Array:B
1),0))

which is an array formula, it should be committed with Ctrl-Shift-Enter, not
just Enter.

--
HTH

Bob Phillips

(remove xxx from email address if mailing direct)

"D7ONO" wrote in message
...
with the data i have i firstly have to do the lookup by using column a to
match the data however columns b also have to match as they can be
different
which is why line 3 is correct (colB is 245 on both sheets) whereas line 2
on
the array column b is 244 this is why i need a formula to search on column
b
after the initial lookup.

hope this makes sense

"broro183" wrote:


Hi,
As Bob has said, vlookup isn't that smart - & I may be slightly off
track here, but why is line 3 the correct match?
If it's b/c this row (ie column A value & column B value) is identical
in both the table & the array, what is the point of returning column B
(of array) in column C of the Table (you could just type"=B1")?

If your intention is to return a value from an identical row you need
to use a concatenated helper column (eg, cell C1 contains "=A1&"%"&B1")
for your lookup/matching or a sum product formula.

Rob Brockett
NZ
Always learning & the best way to learn is to experience...


--
broro183
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http://www.excelforum.com/member.php...o&userid=30068
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http://www.excelforum.com/showthread...hreadid=539199