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"CADManBill" wrote
Now, what if there is more than one "/". Example: ABC1/2x5 1/2 Return 1/2 as .5000 Assume you're referring to the 2nd instance of "1/2" located after the space in the string If A1 contains: ABC1/2x5 1/2 Try in B1: =MID(A1,SEARCH(" ",A1)+1, SEARCH("/",A1,SEARCH(" ",A1))-SEARCH(" ",A1)-1) / MID(A1,SEARCH("/",A1,SEARCH(" ",A1))+1,99) -- Rgds Max xl 97 --- Singapore, GMT+8 xdemechanik http://savefile.com/projects/236895 -- |
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