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Another take on the post, focusing on the line:
I can "Extract" the 1/2, Now I need the "1/2" converted to .5 Assuming the extracted text string "1/2" is in A1, try in B1: =LEFT(A1,SEARCH("/",A1)-1) /RIGHT(A1,LEN(A1)-SEARCH("/",A1)) -- Rgds Max xl 97 --- Singapore, GMT+8 xdemechanik http://savefile.com/projects/236895 -- |
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