Home |
Search |
Today's Posts |
|
#1
![]()
Posted to microsoft.public.excel.worksheet.functions
|
|||
|
|||
![]()
for that i want to get the average of number of very satisfied rating versus
the non very satisfied rating of a single person.. ex. for mike, he has 4 surveys and 2 out of 4 are very satisfied, so clearly its 50% right... thats what i mean for the average, i dont know how to formulate that. Thank you. "T. Valko" wrote: =COUNT(IF((Data!A2:A100=B2)*(Data!B2:B100=C3),Dat a!B2:B100)) Ok, I'm assuming you want the count of "very satisfied" for a particular person. =SUMPRODUCT(--(Data!A2:A100=B2),--(Data!B2:B100=C3)) If you're using Excel 2007: =COUNTIFS(Data!A2:A100,B2,Data!B2:B100,C3) I'm not sure about your average. *Exactly* what do you want to average? -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... Thank you so much for this.. A follow up question, im trying to get the number and average of very satisfied comments of a lis of students.. ex. This is the Data Worksheet A B mike Very Satisfied Kris Very Satisfied Kris Satisfied Mike Satisfied Mike Very Satisfied Mike Not Satisfied Tamy Satisfied Tamy Satisfied and this is my formula : This is a cell from a different Worksheet D3 = Very Satisfied =COUNT(IF((Data!A2:A100=B2)*(Data!B2:B100=C3),Data !B2:B100)) Thank you so much! "T. Valko" wrote: For the count: Data in the range A2:A7... C2 = satisified =COUNTIF(A2:A7,C2) For the percentage: Assuming the count formula is in D2... =D2/COUNTA(A2:A7) Format as Percentage -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... Hi Again, Got a question again.. How can i count text or words? Ex. in column A, i got texts that is equal to "Very Satisfied" and "Satisfied" and others. A Very Satisfied Satisfied Not Satisfied Very Satisfied Very Satisfied Satisfied How can i count the cells that contains "Very Satisfied"? and is there any way for me to get the Average of "Very Satisfied" against the total number of data that is in column A thank you. :) "T. Valko" wrote: I see that you're using the MS web interface so in the list on the left side select Excel Programming. -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... ahh ok, thank you so much.. and do happen to know where can go i that forum? do u know the link to that furom? thanks. =) "T. Valko" wrote: Hmmm.... I'm not sure. You might be able to do that with an event macro but I don't know how to do it. Try posting this question in the programming forum. If A1 contains a formula make sure you note that in your question. -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... Hi, got a Question again... is there any formula that can automatically create a comment in a cell? ex. A1 = 80% and can we have a comment on that, that automatically that says "Passed" Thanks. "T. Valko" wrote: I have a question for Excel 2003 =AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Da ta!$C:$C,"")) You can't use entire columns as range references in array formulas in Excel 2003. Use a smaller specific range. Try it like this (array entered**) =AVERAGE(IF((Data!A1:A10=B1)*(Data!B1:B10=A2),Data !C1:C10)) ** array formulas need to be entered using the key combination of CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER. -- Biff Microsoft Excel MVP "Hijosdelongi" wrote in message ... Hi, I have a question for Excel 2003 =AVERAGE(IF(AND($A2=Data!$B:$B,B$1=Data!$A:$A),Dat a!$C:$C,"")) Im trying to get the AVERAGE of this and its giving me a #VALUE! error.. $A2 is the name that is suppose to be equal in the Data! worksheet and B$1 is the date that is suppose to be equal in the Data! worksheet. Im trying to use AND in IF for me to have two logical test.. Can you help me with this? Thank you so much! "JE McGimpsey" wrote: One way (array-entered: CTRL-SHIFT-ENTER or CMD-RETURN): =AVERAGE(IF((A3:A45="Photo")*(H3:H45<""),H3:H45)) In article , "Spottkitty" wrote: =AVERAGE(IF($A$3:$A$45="Photo",H3:H45)) This is the array I'm using to try to determine an average. Problem...if the field is blank it's counting it as zero and lowering the results. It figured 79% when it should have been 94%. 94% was returned using the simple average formula. I'm guessing I need to nest something to not count nulls? Help!!! |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|