If the input is in D1, then
=IF(MEDIAN(D1,A1,A2)=D1,125,"whatever answer you want if it isn't 125)
or
=IF(AND(D1=A1,D1<=A2),125,"whatever answer you want if it isn't 125)
--
David Biddulph

"tjb" wrote in message
...
There are three columns of data:
A1:2930.92
A2:2954.54
A3:125

If the user enters a number (or the number is derived from another
formula)
that falls between the value in A1 and the value in A2, I want it to
return
the value from A3.

"Jacob Skaria" wrote:

You havnt told from where 125 came from..If your data is sorted then
check
out help on the function =LOOKUP()

If this post helps click Yes
---------------
Jacob Skaria


"tjb" wrote:

I don't know if this will be a vlookup or something similar but here's
what I
need:

-user enters a number that could range anywhere from 0 to 22667.27
-formula should match whatever number the user entered against an
applicable
range and then return a different number
-For example a user enters 2931.15
-Formula should return a value of "125" since the user defined number
falls
between 2930.92 and 2954.54
-Formula should return a value of "126" if user enters 2970.12 because
that
value falls between 2954.55 and 2978.18

I have a list of hundreds of different ranges like this going from 0
all the
way to 22667.27.

Please help! Thanks.