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Default Averaging numbers in a column while excluding blank spaces and zer

=IF(COUNTIF(G2:G13,"0"),SUMIF(G2:G13,"0",G2:G13 )/COUNTIF(G2:G13,"0"),"")

No need to repeat the range in SUMIF. Can be reduced to:

=IF(COUNTIF(G2:G13,"0"),SUMIF(G2:G13,"0")/COUNTIF(G2:G13,"0"),"")

--
Biff
Microsoft Excel MVP


"T. Valko" wrote in message
...
Try one of these:

=IF(COUNTIF(G2:G13,"0"),SUMIF(G2:G13,"0",G2:G13)/COUNTIF(G2:G13,"0"),"")

This is an array formula** :

=IF(COUNTIF(G2:G13,"0"),AVERAGE(IF(G2:G130,G2:G1 3)),"")

** array formulas need to be entered using the key combination of
CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the
SHIFT key then hit ENTER.

This one will return a 0 if no entries are greater than 0. The other
formulas will return a blank:

=SUM(G2:G13)/MAX(1,COUNTIF(G2:G13,"0"))

--
Biff
Microsoft Excel MVP


"c. murphy" <c. wrote in message
...
I am using office 2003 and have the numbers 0, 0, 5, 0, 0, 5, 0, 0, 5, 0,
0,
5 in column G. How do I average only those blocks that contain a number
greater than zero no matter what blocks in that column might contain a
number
greater than zero?

Thank You





 
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