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=IF(RIGHT(TEXT(A1,"0.000"),3)="010",D1,0) On Jan 27, 12:00*am, MIKE F wrote: i am referencing a 9 digit number. *they are all formated as follows: 123456.xxx where xxx can be 001 thru 012. *The formula works for all values other than the "010". *In the formula bar for the referenced "A" column cell it drops the last zero even though the sheet is formatted and displays as 123456.010 Thanks. "Kassie" wrote: If it is dropped, Excel will evaluate ?01, iso 010. *Iow, if your number was 1234010, and the last 0 is dropped, Excel will evaluate 401, and of course return 0. *That would depend on the number of digits in your number? *Excel handles 15 digits only. *On the other hand, it would then do the same with the other numbers as well? *What is the exact number that you are evaulating? -- Hth Kassie Kasselman Change xxx to hotmail "MIKE F" wrote: I had previously checked the formula to make aure that i was using "0" as opposed to "O". I even tried to apply the formula in a new workbook to make sure by copying your formula and got the same results. *It always returns "0" into my formula cell. *When i click on the reference cell (A1) when it ends in the "010" value it drops that last value (0) from the formula bar. *Could this be the problem? "Kassie" wrote: =if(RIGHT(A1,3)="010",$D1,"0") works for me? Sure you did not use an O, iso a 0? -- Hth Kassie Kasselman Change xxx to hotmail "MIKE F" wrote: I am trying to write an if formula based on the following. =IF(RIGHT($A1,3)="001",$D1,"0") I have successfully written that formula for all values that end in the A column with "001" thru "009" and "011" & "012". *The problem I am having is with "010". *It always retunns 0 into my formula cell. * Please help! |
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