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Default IF Function based on right value

try this

=IF(RIGHT(TEXT(A1,"0.000"),3)="010",D1,0)




On Jan 27, 12:00*am, MIKE F wrote:
i am referencing a 9 digit number. *they are all formated as follows:
123456.xxx where xxx can be 001 thru 012. *The formula works for all values
other than the "010". *In the formula bar for the referenced "A" column cell
it drops the last zero even though the sheet is formatted and displays as
123456.010

Thanks.

"Kassie" wrote:
If it is dropped, Excel will evaluate ?01, iso 010. *Iow, if your number was
1234010, and the last 0 is dropped, Excel will evaluate 401, and of course
return 0. *That would depend on the number of digits in your number? *Excel
handles 15 digits only. *On the other hand, it would then do the same with
the other numbers as well? *What is the exact number that you are evaulating?


--
Hth


Kassie Kasselman
Change xxx to hotmail


"MIKE F" wrote:


I had previously checked the formula to make aure that i was using "0" as
opposed to "O".
I even tried to apply the formula in a new workbook to make sure by copying
your formula and got the same results. *It always returns "0" into my formula
cell. *When i click on the reference cell (A1) when it ends in the "010"
value it drops that last value (0) from the formula bar. *Could this be the
problem?
"Kassie" wrote:


=if(RIGHT(A1,3)="010",$D1,"0") works for me?


Sure you did not use an O, iso a 0?
--
Hth


Kassie Kasselman
Change xxx to hotmail


"MIKE F" wrote:


I am trying to write an if formula based on the following.


=IF(RIGHT($A1,3)="001",$D1,"0")


I have successfully written that formula for all values that end in the A
column with "001" thru "009" and "011" & "012". *The problem I am having is
with "010". *It always retunns 0 into my formula cell. *
Please help!


 
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