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#1
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counting distinct entries with a qualification
I know about the formula
=SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#2
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
try this
=SUMPRODUCT(--(RIGHT(A1:A10,1)="a"))-(COUNTA(A1:A10)-SUM(1/ COUNTIF(A1:A10,A1:A10))) use ctrl +shift + enter On Sep 29, 11:29*am, "Stephen" <none wrote: I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#3
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
I'm sure this is dooable with a non-array sumproduct but in the meantime try
this array formula =COUNT(1/FREQUENCY(IF((B1:B10="a")*(B1:B10<""),MATCH(A1:A1 0,A1:A10,0)),ROW(INDEX(A1:A10,0,0))-ROW(A1)+1)) Array formula are entered using CTRL+Shift+Enter. Mike "Stephen" wrote: I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#4
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counting distinct entries with a qualification
I had no luck with embedding IF into your formula
I used a helper column (C) with =IF(B1="a",A1,"") Then I used =SUM(1/COUNTIF(C1:C10,C1:C10)) - 1 The subtraction of 1 is for the empty cells Column C can be hidden or use a column to the far right. best wishes -- Bernard V Liengme Microsoft Excel MVP http://people.stfx.ca/bliengme remove caps from email "Stephen" <none wrote in message ... I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#5
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
Here's another
=SUM(N(FREQUENCY(IF(B2:B20="a",MATCH(A2:A20,A2:A20 ,0)),MATCH(A2:A20,A2:A20,0))0)) entered with ctrl + shift & enter -- Regards, Peo Sjoblom "Stephen" <none wrote in message ... I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#6
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
Hi,
Here is another array entered solution: =SUM(1/(IF(B1:B10="a",1,10^10)*COUNTIF(A1:A10,A1:A10))) and technically this returns 4.00000000005 for your data so you could apply the round function: =ROUND(SUM(1/(IF(B1:B10="a",1,10^10)*COUNTIF(A1:A10,A1:A10))),2 ) -- Thanks, Shane Devenshire "Stephen" wrote: I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#7
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
It doesn't work.
Try it with these values in A1:B10 2 a 2 b 2 c 2 a 2 b 2 c 2 a 2 b 2 c 2 a It should return 1 but it returns 0.4 -- Regards, Peo Sjoblom "ShaneDevenshire" wrote in message ... Hi, Here is another array entered solution: =SUM(1/(IF(B1:B10="a",1,10^10)*COUNTIF(A1:A10,A1:A10))) and technically this returns 4.00000000005 for your data so you could apply the round function: =ROUND(SUM(1/(IF(B1:B10="a",1,10^10)*COUNTIF(A1:A10,A1:A10))),2 ) -- Thanks, Shane Devenshire "Stephen" wrote: I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
#8
Posted to microsoft.public.excel.worksheet.functions
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counting distinct entries with a qualification
Thanks to all who offered solutions, particularly Mike H and Peo Sjoblom
whose formulas worked well. The latter is shorter, whilst the former copes with blanks in column A. It's great to get such good quality help. This is much appreciated. Thanks, Stephen "Stephen" <none wrote in message ... I know about the formula =SUM(1/COUNTIF(A1:A10,A1:A10)) for counting the number of distinct (text) entries in the range A1:A10 (where there are no blanks). What I need is a worksheet formula to do a similar job, but only taking into consideration rows where B1:B10 contain "a". So, the following data would give a result of 4. John a Fred a Sally Jane Jane a John a Fred Alan a Tim Alan a Any suggestions, please? Stephen |
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