Good afternoon, this is not a homework question, I am trying to brush
up on statistics for my job. I am having a problem with a question. A
4 year college will accept any student ranked in the top 60% on a
National Examination. If the test score is normally distributed with a
mean of 500 and a standard deviation of 100, what is the cutoff score
for acceptance?

The book says 475. If I take =NORMSINV(1-A1) where A1 houses 0.6 it
gives me -0.25 the z-score but how do I come up with 475? If I check
the equasion with the answer =(475-500)/100 it will give me -0.25. How
do I solve the unknown?

Thanks in advance
PJ