hello all, i have a row of 18 numbers that update autmatically and give me a
number increasing by 1 if the statement is true, if false, i get a 0. i would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last number
over 0.
the below example would be after 3 different days of inputs, as you can see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

Adapt this

=LOOKUP(2,1/((BA3:BR3<"")*(BA3:BR3<0)),BA3:BR3)


if there can be no empty cells within you can use


=LOOKUP(2,1/(BA3:BR3<0),BA3:BR3)


--


Regards,


Peo Sjoblom




"Joe" wrote in message
...
hello all, i have a row of 18 numbers that update autmatically and give
me a
number increasing by 1 if the statement is true, if false, i get a 0. i
would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last
number
over 0.
the below example would be after 3 different days of inputs, as you can
see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

Try this array formula (assuming row 1. Change as needed):

=INDEX(A1:R1,1,MAX(--(A1:R1<0)*COLUMN(A1:R1)))

For an array formula, instead of Enter, you have to press Ctrl + Shift +
Enter. If you do it right, Excel will add curly braces around the formula.

Hope this helps,

Hutch

"Joe" wrote:

hello all, i have a row of 18 numbers that update autmatically and give me a
number increasing by 1 if the statement is true, if false, i get a 0. i would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last number
over 0.
the below example would be after 3 different days of inputs, as you can see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

Try this:

=LOOKUP(2,1/BA3:BR3,BA3:BR3)

--
Biff
Microsoft Excel MVP


"Joe" wrote in message
...
hello all, i have a row of 18 numbers that update autmatically and give
me a
number increasing by 1 if the statement is true, if false, i get a 0. i
would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last
number
over 0.
the below example would be after 3 different days of inputs, as you can
see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

Doesn't work if the last value is < 1 but 0

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my addy)



"T. Valko" wrote in message
...
Try this:

=LOOKUP(2,1/BA3:BR3,BA3:BR3)

--
Biff
Microsoft Excel MVP


"Joe" wrote in message
...
hello all, i have a row of 18 numbers that update autmatically and give
me a
number increasing by 1 if the statement is true, if false, i get a 0. i
would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last
number
over 0.
the below example would be after 3 different days of inputs, as you can
see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

This should take care of that:

=LOOKUP(1E100,1/BA3:BR3,BA3:BR3)


--
Biff
Microsoft Excel MVP


"Bob Phillips" wrote in message
...
Doesn't work if the last value is < 1 but 0

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my
addy)



"T. Valko" wrote in message
...
Try this:

=LOOKUP(2,1/BA3:BR3,BA3:BR3)

--
Biff
Microsoft Excel MVP


"Joe" wrote in message
...
hello all, i have a row of 18 numbers that update autmatically and give
me a
number increasing by 1 if the statement is true, if false, i get a 0. i
would
like to know of a formula that will give me the last number in the
string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last
number
over 0.
the below example would be after 3 different days of inputs, as you can
see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

thank you all for your help, the first one i tried and its good. i have been
trying to figure that out for a few months now and was getting nowhere. keep
up the good work.

Joe

"T. Valko" wrote:

This should take care of that:

=LOOKUP(1E100,1/BA3:BR3,BA3:BR3)


--
Biff
Microsoft Excel MVP


"Bob Phillips" wrote in message
...
Doesn't work if the last value is < 1 but 0

--
---
HTH

Bob


(there's no email, no snail mail, but somewhere should be gmail in my
addy)



"T. Valko" wrote in message
...
Try this:

=LOOKUP(2,1/BA3:BR3,BA3:BR3)

--
Biff
Microsoft Excel MVP


"Joe" wrote in message
...
hello all, i have a row of 18 numbers that update autmatically and give
me a
number increasing by 1 if the statement is true, if false, i get a 0. i
would
like to know of a formula that will give me the last number in the
string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last
number
over 0.
the below example would be after 3 different days of inputs, as you can
see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4

On Thu, 1 May 2008 19:04:32 +0100, "Bob Phillips"
wrote:

Doesn't work if the last value is < 1 but 0

While your statement is true, I don't see how that would occur given the OP's
description.
--ron

joe test

"Joe" wrote:

hello all, i have a row of 18 numbers that update autmatically and give me a
number increasing by 1 if the statement is true, if false, i get a 0. i would
like to know of a formula that will give me the last number in the string
excluding the 0's.
example is columns BA3:BR3 and in column BS3 i would like to see last number
over 0.
the below example would be after 3 different days of inputs, as you can see
it does not take the 0 but the last whole digit in the string.

your help would be greatly appreciated
thank you

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
0 0 =2

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 0 =3

ba bb bc bd be bf bg bg bi bj bk bl bm bn bo bp bq br
bs
0 1 2 3 4 5 6 7 8 0 1 2 3 0 1 2
3 4 =4