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Thanks a lot folks,
You are great!! "Peo Sjoblom" wrote in message ... Column with values starting in A2 going down =OFFSET($A$2,COLUMN(A:A)-1,) copy across and it will return A2, A3, A4 etc Row with values starting in D2 =OFFSET($D$2,,ROW(1:1)-1,) copy down and it will return D2, E2, F2 etc -- Regards, Peo Sjoblom "markx" wrote in message ... Thanks Julie, In fact, I've tested this function just before, but as you pointed it out, it doesn't work by dragging it. I remember that some time ago, I've found somewhere on the net two functions that work as I would like, but concern only transposing rows to columns. One involves INDIRECT, ADDRESS and ROW functions, the other goes with INDEX and ROW function. Unfortunately I can't find them back right now to quote them directly. While searching, I've just found something similar on the groups, I post it here for the illustration purposes, maybe this could help you imagine a "general" formula covering my problem (unfortunately I'm unable to do it by myself:-(: =INDEX(Sheet1!$1:$1,ROW()*2-1) = this one is supposed to skip every second value, still row to column or =INDIRECT("Summary!"&ADDRESS(38;ROW(1:1);4)) = still row to column, a particular case or =INDIRECT("Summary!"&SUBSTITUTE(ADDRESS(1;ROW(1:1) ;4);"1";"")&"38") = still row to column, same post as before Thanks once again for your help and FU on this! Mark --------------------- "JulieD" wrote in message ... Hi not sure if it fits the description of not too complex and doesn't work by dragging, but there is a transpose function say you have ........A..........B 1.....Cat........10 2.....Dog.......15 3....Rat..........20 and you want to transpose this table to the range A5:C6 select A5:C6 type =TRANSPOSE(A1:B3) and then press Control & Shift & Enter - not just Enter and the data will be transposed. Cheers JulieD "markx" wrote in message ... Hello everybody, I'm looking for a formula (not VBA nor "Paste Special/Transpose") that would transpose columns to rows (or vice versa) by simple dragging of the cell. Are you aware of any, hopefully not too complex? Thanks a lot for your help on this, Mark |
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