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#1
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Any number above 15 returns false when it should be true
=IF((16.99-16)=0.99,10,0)
In this function, any number from (1.99-1) through (15.99-15) works and any number above (16.99-16) fails. |
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#2
Posted to microsoft.public.excel.worksheet.functions
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Any number above 15 returns false when it should be true
It's because the underlying value is not 0.99, it's in fact
0.989999999999998 You could remedy this in your case by using this =IF(ROUND(16.99-16,2)=0.99,10,0) that's the way computer works, see these links for an explanation http://www.mcgimpsey.com/excel/pennyoff.html http://www.cpearson.com/excel/rounding.htm -- Regards, Peo Sjoblom "tlaurie777" wrote in message ... =IF((16.99-16)=0.99,10,0) In this function, any number from (1.99-1) through (15.99-15) works and any number above (16.99-16) fails. |
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#3
Posted to microsoft.public.excel.worksheet.functions
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Any number above 15 returns false when it should be true
try
IF(ROUND(16.99-16,2)=0.99,10,0) -- Don Guillett Microsoft MVP Excel SalesAid Software "tlaurie777" wrote in message ... =IF((16.99-16)=0.99,10,0) In this function, any number from (1.99-1) through (15.99-15) works and any number above (16.99-16) fails. |
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