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#1
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Hello,
I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#2
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=MIN(COUNTIF(A1:A8,"Xxx"),COUNTIF(A1:A8,"Aaa"))
"Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#3
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So...you want to know how many times the same 2 values appear consecutively
exactly twice? In your example, you are counting Aaa followed by Xxx because that sequence appears 2 times, is that right? "Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#4
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I'll try to be more precise :) I *do not know* how many times Aaa is folowed
by Xxx - that's what I want to know :) The fact the sequence appears twice is just because I gave such example :) I have lots of different pairs and I would like to know how many times given pair occurs within the given range (it can be more than 8 cells - in fact the matrix has [you - just kidding :)] several rows and columns filled with the values). -- Piotrek So...you want to know how many times the same 2 values appear consecutively exactly twice? In your example, you are counting Aaa followed by Xxx because that sequence appears 2 times, is that right? "Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#5
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![]() Thank you Mama :) But that's not exactly what I look for. Your function for, e.g. Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Xxx shows "3" although it should give "2", because we have just 2 pairs of Aaa and Xxx. Thank you anyway :) -- Piotrek =MIN(COUNTIF(A1:A8,"Xxx"),COUNTIF(A1:A8,"Aaa")) "Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#6
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OK, so do you know the two values that you want to find in sequence, eh?
I created a new first column for some sample data containing row numbers and titled Idx, titled your first column ColA, and then saved the file. Then I opened Access and imported your data into a table named DataRange. Then I created a query like so using SQL mode: SELECT Count(*) AS NumPairs FROM Datarange AS t1 WHERE (((Exists (select * from datarange t2 where t2.idx = t1.idx+1 and t2.ColA = "Xxx"))<False) AND ((t1.colA)="Aaa")); "Piotrek" wrote: I'll try to be more precise :) I *do not know* how many times Aaa is folowed by Xxx - that's what I want to know :) The fact the sequence appears twice is just because I gave such example :) I have lots of different pairs and I would like to know how many times given pair occurs within the given range (it can be more than 8 cells - in fact the matrix has [you - just kidding :)] several rows and columns filled with the values). -- Piotrek So...you want to know how many times the same 2 values appear consecutively exactly twice? In your example, you are counting Aaa followed by Xxx because that sequence appears 2 times, is that right? "Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#7
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Let me translate that query for you - first Access adds needless sets of
parentheses, so I'll simplify it SELECT Count(*) AS NumPairs FROM Datarange AS t1 WHERE Exists (select * from datarange t2 where t2.idx = t1.idx+1 and t2.ColA = "Xxx"<False) AND t1.colA="Aaa"; The outer part is SELECT Count(*) AS NumPairs FROM Datarange AS t1 WHERE Exists (...) AND t1.colA="Aaa"; So we want to count the # of times Aaa shows up. However, we want to limit it to the times it is FOLLOWED by Xxx, so the inner part says WHERE Exists (...) and what must exist is this select * from datarange t2 where t2.idx = t1.idx+1 and t2.ColA = "Xxx"<False which means that anytime Aaa appears, we want to only consider the times that the row with the next higher Idx (i.e., the next row) must have an Xxx in it For your purposes, change DataRange to whatever you name your table. You have to have a column that numbers the riws. If you don't name it Idx, then change all the Idx entries to whatever you name your column. Finally, change all the references to ColA to whatever you name your column of actual data. "Duke Carey" wrote: OK, so do you know the two values that you want to find in sequence, eh? I created a new first column for some sample data containing row numbers and titled Idx, titled your first column ColA, and then saved the file. Then I opened Access and imported your data into a table named DataRange. Then I created a query like so using SQL mode: SELECT Count(*) AS NumPairs FROM Datarange AS t1 WHERE (((Exists (select * from datarange t2 where t2.idx = t1.idx+1 and t2.ColA = "Xxx"))<False) AND ((t1.colA)="Aaa")); "Piotrek" wrote: I'll try to be more precise :) I *do not know* how many times Aaa is folowed by Xxx - that's what I want to know :) The fact the sequence appears twice is just because I gave such example :) I have lots of different pairs and I would like to know how many times given pair occurs within the given range (it can be more than 8 cells - in fact the matrix has [you - just kidding :)] several rows and columns filled with the values). -- Piotrek So...you want to know how many times the same 2 values appear consecutively exactly twice? In your example, you are counting Aaa followed by Xxx because that sequence appears 2 times, is that right? "Piotrek" wrote: Hello, I have a little problem with counting pairs of values in vertically adjacent cells, hope you can help... Cells from A1 to A8 contain Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Yyy. I have 24 similar columns. Generally, odd rows contain Aaas or Bbbs and even ones - only Xxxs or Yyys. Is there a way to count the amount of *pairs* of e.g. Aaas and Xxxs? (He 2 pairs) I'll be very grateful for any clues... -- Thank you very much - Piotrek |
#8
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"Piotrek" wrote...
.... But that's not exactly what I look for. Your function for, e.g. Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Xxx shows "3" although it should give "2", because we have just 2 pairs of Aaa and Xxx. =SUMPRODUCT(EXACT(A1:A7,"Aaa")*EXACT(A2:A8,"Xxx")) assuming you want case-sensitive string comparisons. |
#9
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But that's not exactly what I look for.
Your function for, e.g. Aaa, Xxx, Aaa, Xxx, Aaa, Yyy, Bbb, Xxx shows "3" although it should give "2", because we have just 2 pairs of Aaa and Xxx. =SUMPRODUCT(EXACT(A1:A7,"Aaa")*EXACT(A2:A8,"Xxx")) assuming you want case-sensitive string comparisons. Great! I've just made several tests and everything seems to work perfectly so far! Thank you very much for your help, Harlan. Thank you, everyone. Dziekuje! -- Piotrek |
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