I need to have values returned to within 1/16 of an inch, but if the awnser
is 3/8 or 1/2 or 1/4 I need it to say so, all I can get is

3/8 returns as 6/16
1/2 returns as 8/16

is there a way to get around this witin the cell format function

format the cell as #?/#?

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HTH

Bob

(there's no email, no snail mail, but somewhere should be gmail in my addy)



"rflock" wrote in message
...
I need to have values returned to within 1/16 of an inch, but if the awnser
is 3/8 or 1/2 or 1/4 I need it to say so, all I can get is

3/8 returns as 6/16
1/2 returns as 8/16

is there a way to get around this witin the cell format function

On Mon, 20 Aug 2007 14:30:03 -0700, rflock
wrote:

I need to have values returned to within 1/16 of an inch, but if the awnser
is 3/8 or 1/2 or 1/4 I need it to say so, all I can get is

3/8 returns as 6/16
1/2 returns as 8/16

is there a way to get around this witin the cell format function


Format as # ??/?? (or "Up to two digits") and round your result to the nearest
1/16

e.g. =ROUND(your_formula*16,0)/16





--ron