return in fractions with multiple divisors, linear
On Mon, 20 Aug 2007 14:30:03 -0700, rflock
wrote:
I need to have values returned to within 1/16 of an inch, but if the awnser
is 3/8 or 1/2 or 1/4 I need it to say so, all I can get is
3/8 returns as 6/16
1/2 returns as 8/16
is there a way to get around this witin the cell format function
Format as # ??/?? (or "Up to two digits") and round your result to the nearest
1/16
e.g. =ROUND(your_formula*16,0)/16
--ron
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