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#1
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Finding last cell
How would I reflect, in say in sheet2, the last amount in col B, before the
% shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#2
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Finding last cell
=INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<""))))
-- Gary''s Student gsnu200706 "Jim" wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#3
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Finding last cell
You don't need a macro
=LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#4
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Finding last cell
This function will give me the value in the last cell, which is 3.20%. I'm
trying to get the value in the last row before the last row. (sounds kind of dumb) 86,963.25 Thanks Jim "Bob Phillips" wrote in message ... You don't need a macro =LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#5
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Finding last cell
This function will give me the value in the last cell, which is 3.20%. I'm
trying to get the value in the last row before the last row & not necessarly the largest amount. 86,963.25 Thanks Jim "Gary''s Student" wrote in message ... =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) -- Gary''s Student gsnu200706 "Jim" wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#6
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Finding last cell
Very Strange...
On my computer: WinXP / Excel 2002 the formula does return 86,963.25 This formula has been very reliable and works about 99.99847412109370% of the time. -- Gary''s Student gsnu200706 "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row & not necessarly the largest amount. 86,963.25 Thanks Jim "Gary''s Student" wrote in message ... =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) -- Gary''s Student gsnu200706 "Jim" wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#7
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Finding last cell
Thanks for all your help. I just rearranged my worksheet so the % will be in
a different col. Thanks Again Jim "Gary''s Student" wrote in message ... Very Strange... On my computer: WinXP / Excel 2002 the formula does return 86,963.25 This formula has been very reliable and works about 99.99847412109370% of the time. -- Gary''s Student gsnu200706 "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row & not necessarly the largest amount. 86,963.25 Thanks Jim "Gary''s Student" wrote in message ... =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) -- Gary''s Student gsnu200706 "Jim" wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#8
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Finding last cell
But you didn't put the YTD stuff under that table.
Gary''s Student wrote: Very Strange... On my computer: WinXP / Excel 2002 the formula does return 86,963.25 This formula has been very reliable and works about 99.99847412109370% of the time. -- Gary''s Student gsnu200706 "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row & not necessarly the largest amount. 86,963.25 Thanks Jim "Gary''s Student" wrote in message ... =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) -- Gary''s Student gsnu200706 "Jim" wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% -- Dave Peterson |
#9
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Finding last cell
First, you may want to consider putting the YTD info in row 1--then the other
formulas will work ok. And if you use Windows|Freeze Panes, you could make it so that it (and the headers) are always visible. But if your dates are in nice order (ascending), then you could use a formula like: =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) But you can't have any numbers bigger than that last date in column A. Jim wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% -- Dave Peterson |
#10
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Finding last cell
This is what I'm actually working with:
A B C 2 84,926.02 3 2/7/07 95,000.00 1,784.53 4 2/9/07 85,504.54 1,237.79 5 2/13/07 85,910.57 1,643.82 6 2/14/07 86,963.25 2,696.50 7 2/16/07 87,114.37 2,847.62 YTD 3.35% ( =+C7/B2 formula in B9) ANNUAL 26.04% (=+B9/47*365 formula in B10) The YTD & ANNUAL "formula I change whenever I update my sheet. Just trying to find a better way & one is to restructure my spreadsheet. Jim (seem to have lost some brain cells the last 10 years) "Dave Peterson" wrote in message ... First, you may want to consider putting the YTD info in row 1--then the other formulas will work ok. And if you use Windows|Freeze Panes, you could make it so that it (and the headers) are always visible. But if your dates are in nice order (ascending), then you could use a formula like: =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) But you can't have any numbers bigger than that last date in column A. Jim wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% -- Dave Peterson |
#11
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Finding last cell
How about using two additional columns E:F and put those equivalent formulas in
those cells. And then you could actually look back to see how things are progressing. Jim wrote: This is what I'm actually working with: A B C 2 84,926.02 3 2/7/07 95,000.00 1,784.53 4 2/9/07 85,504.54 1,237.79 5 2/13/07 85,910.57 1,643.82 6 2/14/07 86,963.25 2,696.50 7 2/16/07 87,114.37 2,847.62 YTD 3.35% ( =+C7/B2 formula in B9) ANNUAL 26.04% (=+B9/47*365 formula in B10) The YTD & ANNUAL "formula I change whenever I update my sheet. Just trying to find a better way & one is to restructure my spreadsheet. Jim (seem to have lost some brain cells the last 10 years) "Dave Peterson" wrote in message ... First, you may want to consider putting the YTD info in row 1--then the other formulas will work ok. And if you use Windows|Freeze Panes, you could make it so that it (and the headers) are always visible. But if your dates are in nice order (ascending), then you could use a formula like: =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) But you can't have any numbers bigger than that last date in column A. Jim wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% -- Dave Peterson -- Dave Peterson |
#12
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Finding last cell
Actually, thanks to all involved, I played around with the functions given
me & changed the YTD & ANNUAL functions, which I was updating manually to: =INDEX(C:C,MATCH(MAX(B:B),B:B,0))/$B$8 =C31/(INDEX(A6:A400,MATCH(MAX(A6:A400),A6:A400,0))-$A$5)*365 (where $A$5 is 12/31/06) I already have 14 columns across (tracing mutual funds) & think I'll take your suggestion & move the Ytd, etc to another column. Thanks again for all the help. Jim "Dave Peterson" wrote in message ... How about using two additional columns E:F and put those equivalent formulas in those cells. And then you could actually look back to see how things are progressing. Jim wrote: This is what I'm actually working with: A B C 2 84,926.02 3 2/7/07 95,000.00 1,784.53 4 2/9/07 85,504.54 1,237.79 5 2/13/07 85,910.57 1,643.82 6 2/14/07 86,963.25 2,696.50 7 2/16/07 87,114.37 2,847.62 YTD 3.35% ( =+C7/B2 formula in B9) ANNUAL 26.04% (=+B9/47*365 formula in B10) The YTD & ANNUAL "formula I change whenever I update my sheet. Just trying to find a better way & one is to restructure my spreadsheet. Jim (seem to have lost some brain cells the last 10 years) "Dave Peterson" wrote in message ... First, you may want to consider putting the YTD info in row 1--then the other formulas will work ok. And if you use Windows|Freeze Panes, you could make it so that it (and the headers) are always visible. But if your dates are in nice order (ascending), then you could use a formula like: =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) But you can't have any numbers bigger than that last date in column A. Jim wrote: How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% -- Dave Peterson -- Dave Peterson |
#13
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Finding last cell
Maybe you could modifiy Bob's formula to do that. This appears to work okay:
=INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row. (sounds kind of dumb) 86,963.25 Thanks Jim "Bob Phillips" wrote in message ... You don't need a macro =LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#14
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Finding last cell
Thanks, I've got everything working now, just dont know why.
I ve been given the following but not sure what the (2,1 does in #1 & #4, nor the ROW -1 does. More reading & playing to do =LOOKUP(2,1/(B1:B100<""),B1:B100) =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "JMB" wrote in message ... Maybe you could modifiy Bob's formula to do that. This appears to work okay: =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row. (sounds kind of dumb) 86,963.25 Thanks Jim "Bob Phillips" wrote in message ... You don't need a macro =LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#15
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Finding last cell
I'll try to explain further the small changes I did w/Bob's formula (but
check my comments at the end - I would probably move the YTD formulas and stick w/Bob's original formula). =INDEX(B:B,LOOKUP(2,1/(B1:B8<""),ROW(B1:B8))-1) Assume you have the following data in column B: B 1 X 2 58 3 4 4 <empty 5 Joe 6 765 7 <empty 8 <empty Starting in the middle of the formula, (B1:B8<"") will return TRUE/FALSE depending on whether or not the cell is empty. Excel actually stores TRUE as 1 and FALSE as 0, so 1/(B1:B8<"") will yield 1 1 1 #DIV/0 1 1 #DIV/0 #DIV/0 LOOKUP(2,1/(B1:B8<""),ROW(B1:B8), will try to match 2 to the above values (but if it does not find it, it will return the largest value that is smaller than what you are trying to look up -according to Excel help) and will return the corresponding value from the array created by ROW(B1:B8). In actual practice, as long as the value you are trying to look up is greater than all of the values in your lookup vector - it appears Lookup will return the last value (based on what I've seen). So, imagine a table that looks like: 1 1 1 2 1 3 #DIV/0 4 1 5 1 6 #DIV/0 7 #DIV/0 8 So Lookup returns 6 and if we substitute that into the original formula you have =INDEX(B:B,6-1) which will return the value in the 5th row in column B - which hopefully is not blank or empty. So if you have blank/empty cells in between your data there could be problems (which I did not think of until now). Your best bet is probably to move the YTD formulas to the top of column B (or to another column, which I think you said you've already done) and use Bob's original formula to get the last value in column B. "Jim" wrote: Thanks, I've got everything working now, just dont know why. I ve been given the following but not sure what the (2,1 does in #1 & #4, nor the ROW -1 does. More reading & playing to do =LOOKUP(2,1/(B1:B100<""),B1:B100) =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "JMB" wrote in message ... Maybe you could modifiy Bob's formula to do that. This appears to work okay: =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row. (sounds kind of dumb) 86,963.25 Thanks Jim "Bob Phillips" wrote in message ... You don't need a macro =LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
#16
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Finding last cell
I want to thank you very much for the extensive explanation of the formula.
Jim "JMB" wrote in message ... I'll try to explain further the small changes I did w/Bob's formula (but check my comments at the end - I would probably move the YTD formulas and stick w/Bob's original formula). =INDEX(B:B,LOOKUP(2,1/(B1:B8<""),ROW(B1:B8))-1) Assume you have the following data in column B: B 1 X 2 58 3 4 4 <empty 5 Joe 6 765 7 <empty 8 <empty Starting in the middle of the formula, (B1:B8<"") will return TRUE/FALSE depending on whether or not the cell is empty. Excel actually stores TRUE as 1 and FALSE as 0, so 1/(B1:B8<"") will yield 1 1 1 #DIV/0 1 1 #DIV/0 #DIV/0 LOOKUP(2,1/(B1:B8<""),ROW(B1:B8), will try to match 2 to the above values (but if it does not find it, it will return the largest value that is smaller than what you are trying to look up -according to Excel help) and will return the corresponding value from the array created by ROW(B1:B8). In actual practice, as long as the value you are trying to look up is greater than all of the values in your lookup vector - it appears Lookup will return the last value (based on what I've seen). So, imagine a table that looks like: 1 1 1 2 1 3 #DIV/0 4 1 5 1 6 #DIV/0 7 #DIV/0 8 So Lookup returns 6 and if we substitute that into the original formula you have =INDEX(B:B,6-1) which will return the value in the 5th row in column B - which hopefully is not blank or empty. So if you have blank/empty cells in between your data there could be problems (which I did not think of until now). Your best bet is probably to move the YTD formulas to the top of column B (or to another column, which I think you said you've already done) and use Bob's original formula to get the last value in column B. "Jim" wrote: Thanks, I've got everything working now, just dont know why. I ve been given the following but not sure what the (2,1 does in #1 & #4, nor the ROW -1 does. More reading & playing to do =LOOKUP(2,1/(B1:B100<""),B1:B100) =INDIRECT("B"&SUMPRODUCT(MAX((ROW(B1:B1000))*(B1:B 1000<"")))) =INDEX(B:B,MATCH(MAX(A:A),A:A,0)) =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "JMB" wrote in message ... Maybe you could modifiy Bob's formula to do that. This appears to work okay: =INDEX(B:B,LOOKUP(2,1/(B1:B100<""),ROW(B1:B100))-1) "Jim" wrote: This function will give me the value in the last cell, which is 3.20%. I'm trying to get the value in the last row before the last row. (sounds kind of dumb) 86,963.25 Thanks Jim "Bob Phillips" wrote in message ... You don't need a macro =LOOKUP(2,1/(B1:B100<""),B1:B100) -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Jim" wrote in message ... How would I reflect, in say in sheet2, the last amount in col B, before the % shown in in col B, which will change as i add new dates? In my old 123 days to find this cell i would record a macro like goto col B, end down, down,end up. Not sure how to accomplise this in Excel 2003. Thanks, Jim A B C D 1 2/7/07 86,051.28 1,784.53 2.12% 2 2/9/07 85,504.54 1,237.79 1.47% 3 2/13/07 85,910.57 1,643.82 1.95% 4 2/14/07 86,963.25 2,696.50 3.20% YTD 3.20% |
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