Or slightly shorter:

=CHOOSE(MEDIAN(1,B16/5-4,12),0.099,0.111,0.137,0.2,0.3,0.675,0.852,1.405, 2.389,3.869,6.451,0)

JMB wrote:

30 through 33 returns 0.099 - it s/b 0.111 according to the OP. The ranges
are off a little. Also, w/ values under 29 your formula generates an error
as the first parameter for Choose will be 0 or negative. And values over 89
will return an error instead of 0 as the OP indicated (the first parameter
will exceed the number of elements in the choose function).

With some small changes, however, I believe it will work:
=CHOOSE(MIN(MAX(1,ROUNDUP((B16-24)/5,0)),12), 0.099, 0.111, 0.137, 0.2, 0.3,
0.675, 0.852, 1.405, 2.389, 3.869, 6.451,0)

Personally, I would prefer a lookup table as it would be easier to maintain
and update, but that is only my opinion.


"Greg Wilson" wrote:

Forget the table and VLookup. Try:

=CHOOSE(INT((B16 - 24)/5), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852,
1.405, 2.389, 3.869, 6.451)

Regards,
Greg Wilson

"Greg" wrote:

Hi all,
Can anyone assist me with a workaround for the following formula. As you
will be able to see it will not work because of the limit of 8 nested if
statements, but I was hoping someone knew of something that would work
without me using two different cells. The formula is
=if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0)))))))))))