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#1
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Hi all,
Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#2
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put these values in cells A1:B12
-500 0.111 29 0.137 34 0.200 39 0.300 44 0.675 49 0.852 54 1.405 59 2.389 64 3.869 69 6.451 74 0.000 79 -1 then use this formula =VLOOKUP(B16,A1:B12,2) "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#3
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VLOOKUP would be your best bet.
-- David Biddulph "Greg" wrote in message ... Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#4
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Set up a 2 column table like this:
..............A.............B 1..........0.......... 0.099 2........30.......... 0.111 3........35.......... 0.137 4........40.......... 0.2 5........45.......... 0.3 6........50.......... 0.675 7........55.......... 0.852 8........60.......... 1.405 9........65.......... 2.389 10......70.......... 3.869 11......75.......... 6.451 Then: =IF(B1679,0,VLOOKUP(B16,A1:B11,2) Biff "Greg" wrote in message ... Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#5
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considering B16 is non-negative number
table A B 1 29 0.099 2 34 0.111 3 39 0.137 4 44 0.2 5 49 0.3 6 54 0.675 7 59 0.852 8 64 1.405 9 69 2.389 10 74 3.869 11 79 6.451 B16 = IF(B1679,0,LOOKUP(B16,$A$1:$A$11,$B$1:$B$11)) "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#6
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This is misleading - you imply that the formula goes into cell B16, but
you can't put the formula there as it refers to that cell. Pete driller wrote: considering B16 is non-negative number table A B 1 29 0.099 2 34 0.111 3 39 0.137 4 44 0.2 5 49 0.3 6 54 0.675 7 59 0.852 8 64 1.405 9 69 2.389 10 74 3.869 11 79 6.451 B16 = IF(B1679,0,LOOKUP(B16,$A$1:$A$11,$B$1:$B$11)) "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#7
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The OP will get an error for values less than 29. Since Lookup returns the
largest value that is *smaller* than or equal to the lookup value - I think your table should start w/ a number that will always be smaller than the smallest possible criteria - which could be done w/ a formula: =0+((B16-1)*(B16<0)) The rest of the ranges would be as Biff posted. "driller" wrote: considering B16 is non-negative number table A B 1 29 0.099 2 34 0.111 3 39 0.137 4 44 0.2 5 49 0.3 6 54 0.675 7 59 0.852 8 64 1.405 9 69 2.389 10 74 3.869 11 79 6.451 B16 = IF(B1679,0,LOOKUP(B16,$A$1:$A$11,$B$1:$B$11)) "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#8
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Forget the table and VLookup. Try:
=CHOOSE(INT((B16 - 24)/5), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852, 1.405, 2.389, 3.869, 6.451) Regards, Greg Wilson "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#9
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30 through 33 returns 0.099 - it s/b 0.111 according to the OP. The ranges
are off a little. Also, w/ values under 29 your formula generates an error as the first parameter for Choose will be 0 or negative. And values over 89 will return an error instead of 0 as the OP indicated (the first parameter will exceed the number of elements in the choose function). With some small changes, however, I believe it will work: =CHOOSE(MIN(MAX(1,ROUNDUP((B16-24)/5,0)),12), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852, 1.405, 2.389, 3.869, 6.451,0) Personally, I would prefer a lookup table as it would be easier to maintain and update, but that is only my opinion. "Greg Wilson" wrote: Forget the table and VLookup. Try: =CHOOSE(INT((B16 - 24)/5), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852, 1.405, 2.389, 3.869, 6.451) Regards, Greg Wilson "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#10
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Or slightly shorter:
=CHOOSE(MEDIAN(1,B16/5-4,12),0.099,0.111,0.137,0.2,0.3,0.675,0.852,1.405, 2.389,3.869,6.451,0) JMB wrote: 30 through 33 returns 0.099 - it s/b 0.111 according to the OP. The ranges are off a little. Also, w/ values under 29 your formula generates an error as the first parameter for Choose will be 0 or negative. And values over 89 will return an error instead of 0 as the OP indicated (the first parameter will exceed the number of elements in the choose function). With some small changes, however, I believe it will work: =CHOOSE(MIN(MAX(1,ROUNDUP((B16-24)/5,0)),12), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852, 1.405, 2.389, 3.869, 6.451,0) Personally, I would prefer a lookup table as it would be easier to maintain and update, but that is only my opinion. "Greg Wilson" wrote: Forget the table and VLookup. Try: =CHOOSE(INT((B16 - 24)/5), 0.099, 0.111, 0.137, 0.2, 0.3, 0.675, 0.852, 1.405, 2.389, 3.869, 6.451) Regards, Greg Wilson "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#11
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this is nice, many responded to your post Greg...cheers
To mislead may mean to challenge try this again! considering your input cell B16 is not blank and has non-negative number (=0) table A B 1 29 0.099 2 34 0.111 3 39 0.137 4 44 0.2 5 49 0.3 6 54 0.675 7 59 0.852 8 64 1.405 9 69 2.389 10 74 3.869 11 79 6.451 B16=0 copy/paste formula below on another cell = IF(B1679,0,LOOKUP(B16,$A$1:$A$11,$B$1:$B$11)) cheers... "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
#12
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![]() sorry guys, i paste the old formula with Lookup versatility... here it is.. place formula say on cell H1 (good on as-is basis the step 5 increment but can be modify ) =IF(G179,0,IF(G1LOOKUP(G1,$A$1:$A$12,$A$1:$A$12) ,LOOKUP((G1+5),$A$1:$A$12,$B$1:$B$12),LOOKUP((G1), $A$1:$A$12,$B$1:$B$12))) place your lookup value on cell G1 (=0) your table A B 1 0 0.099 2 29 0.099 3 34 0.111 4 39 0.137 5 44 0.2 6 49 0.3 7 54 0.675 8 59 0.852 9 64 1.405 10 69 2.389 11 74 3.869 12 79 6.451 if u want to adjust the data on Column B, no need to adjust the formula... "Greg" wrote: Hi all, Can anyone assist me with a workaround for the following formula. As you will be able to see it will not work because of the limit of 8 nested if statements, but I was hoping someone knew of something that would work without me using two different cells. The formula is =if(B16<=29,0.099,if(b16<=34,0.111,if(b16<=39,0.13 7,if(b16<=44,0.2,if(b16<=49,0.3,if(b16<=54,0.675,i f(b16<=59,0.852,if(b16<=64,1.405,if(b16<=69,2.389, if(b16<=74,3.869,if(b16<=79,6.451,0))))))))))) |
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