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Default To be got Alphabetic

Moideen wrote:

Auric__ Wrote:
Moideen wrote:
-
We are Maintaining cost in English Letters, Kindly Help to get COST
on Coloumn2

Examples,

A : 1
B : 2
C : 3
D : 4
F : 5

If I Entered 242 on Coloumn1 Need Automatic Shown BDB on Coloumn2-


Put this in the sheet's object in the VBA editor:

[snip]
Edit the 'costs' array to fit. (The hashes are there to indicate data
entry errors. If you don't want them, don't delete them -- change them
to "".)

If this is meant to apply to the entire workbook, put this in the
ThisWorkbook object instead:

[snip]
Thank you very much, This function working is smoothly but one problem,
If i entered 12.3 , Need Letter : AB.C or AB/C Please Help me.


I looked through the functions, and found the SUBSTITUTE spreadsheet
function. It should be faster than my code, and should also be easier to
understand. Paste this into B1 and then copy down (one line, watch the word
wrap):

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F")

This can be extended by adding on more levels of SUBSTITUTE if necessary.

If you'd rather stick with VBA, this works similarly:

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), 3, "C"), _
4, "D"), 5, "F")
Next
End Sub

(Forget about what I posted before. Wasted effort on my part, mostly.)

--
I don't believe in *lots* of invisible things
that are supposed to make me happy.
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Posts: 36
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Quote:
Originally Posted by Auric__ View Post
Moideen wrote:

Auric__ Wrote:
Moideen wrote:
-
We are Maintaining cost in English Letters, Kindly Help to get COST
on Coloumn2

Examples,

A : 1
B : 2
C : 3
D : 4
F : 5

If I Entered 242 on Coloumn1 Need Automatic Shown BDB on Coloumn2-


Put this in the sheet's object in the VBA editor:

[snip]
Edit the 'costs' array to fit. (The hashes are there to indicate data
entry errors. If you don't want them, don't delete them -- change them
to "".)

If this is meant to apply to the entire workbook, put this in the
ThisWorkbook object instead:

[snip]
Thank you very much, This function working is smoothly but one problem,
If i entered 12.3 , Need Letter : AB.C or AB/C Please Help me.


I looked through the functions, and found the SUBSTITUTE spreadsheet
function. It should be faster than my code, and should also be easier to
understand. Paste this into B1 and then copy down (one line, watch the word
wrap):

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F")

This can be extended by adding on more levels of SUBSTITUTE if necessary.

If you'd rather stick with VBA, this works similarly:

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), 3, "C"), _
4, "D"), 5, "F")
Next
End Sub

(Forget about what I posted before. Wasted effort on my part, mostly.)

--
I don't believe in *lots* of invisible things
that are supposed to make me happy.
Thanks a lot...
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Quote:
Originally Posted by Moideen View Post
Thanks a lot...
Dear Auric,

I Tried with the below mentioned VBA code "0" not showing.

Eg : 1.550 , Shown only : A.FF, To be Shown : A.FFS

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), 3, "C"), _
4, "D"), 5, "F"), 0, "S")
Next
End Sub
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Default To be got Alphabetic

On Mon, 2 Jul 2012 14:49:01 +0000, Moideen wrote:

Dear Auric,

I Tried with the below mentioned VBA code "0" not showing.

Eg : 1.550 , Shown only : A.FF, To be Shown : A.FFS


That makes perfect sense, given the specifications you have provided.

================
A : 1
B : 2
C : 3
D : 4
F : 5
================================

It seems that you have only provided letter values for the numerals 1 to 5. And in a later post you indicated that you wanted the decimal (.) to be preserved.
Why would you expect any other numerals to be taken into account?

If you provide incomplete specifications, you should not be surprised that the results do not take into account requirements that you do not specify. I would suggest that, if there are other digits that you want to convert to letters, you include ALL of them in a single post.



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Default To be got Alphabetic

Moideen wrote:

I Tried with the below mentioned VBA code "0" not showing.

Eg : 1.550 , Shown only : A.FF, To be Shown : A.FFS

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), 3, "C"), _
4, "D"), 5, "F"), 0, "S")
Next
End Sub


As I said before, you can extend the function by adding more levels of
SUBSTITUTE or Replace as necessary -- meaning you need to *actually add
another copy of the keyword*, not just the info to be replaced:

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")

If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), _
3, "C"), 4, "D"), 5, "F"), 0, "S")

If you need a seventh replacement, you need a seventh SUBSTITUTE/Replace...
but this is going to get unwieldy pretty fast, especially if you're replacing
*every* digit with a letter.

If you have more than this, you should go back to looking the digits up in an
array, similar (but not identical) to my first reply.

--
Here is an idea for you geniuses:
Point your weapons at the bugs and shoot.
If they die, the guns work. If not, grab a brick.


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Posts: 36
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Quote:
Originally Posted by Auric__ View Post
Moideen wrote:

I Tried with the below mentioned VBA code "0" not showing.

Eg : 1.550 , Shown only : A.FF, To be Shown : A.FFS

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), 3, "C"), _
4, "D"), 5, "F"), 0, "S")
Next
End Sub


As I said before, you can extend the function by adding more levels of
SUBSTITUTE or Replace as necessary -- meaning you need to *actually add
another copy of the keyword*, not just the info to be replaced:

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")

If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), _
3, "C"), 4, "D"), 5, "F"), 0, "S")

If you need a seventh replacement, you need a seventh SUBSTITUTE/Replace...
but this is going to get unwieldy pretty fast, especially if you're replacing
*every* digit with a letter.

If you have more than this, you should go back to looking the digits up in an
array, similar (but not identical) to my first reply.

--
Here is an idea for you geniuses:
Point your weapons at the bugs and shoot.
If they die, the guns work. If not, grab a brick.
Dear Auric,

We Need Always 3 Digits.This function only comming 2 Digits, Pls Advice me on this matter.

Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")
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Default To be got Alphabetic

Moideen wrote:

We Need Always 3 Digits.This function only comming 2 Digits, Pls Advice
me on this matter.

Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")


Works for me. Shrug. Try switching to the VBA solution:

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), _
3, "C"), 4, "D"), 5, "F"), 0, "S")
Next
End Sub

--
Where is your savior now?
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Quote:
Originally Posted by Auric__ View Post
Moideen wrote:

We Need Always 3 Digits.This function only comming 2 Digits, Pls Advice
me on this matter.

Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")


Works for me. Shrug. Try switching to the VBA solution:

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), _
3, "C"), 4, "D"), 5, "F"), 0, "S")
Next
End Sub

--
Where is your savior now?
Not Getting..

Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS
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Posts: 36
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[quote=Auric__;1603366]Moideen wrote:

We Need Always 3 Digits.This function only comming 2 Digits, Pls Advice
me on this matter.

Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS

=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(SUBST ITUTE(SUBSTITUTE
(A1,1,"A"),2,"B"),3,"C"),4,"D"),5,"F"),0,"S")


Works for me. Shrug. Try switching to the VBA solution:

Private Sub Worksheet_Change(ByVal Target As Range)
For Each cell In Target
If cell.Column = 1 Then cell.Offset(0, 1).Value = Replace(Replace( _
Replace(Replace(Replace(Replace(cell.Value, 1, "A"), 2, "B"), _
3, "C"), 4, "D"), 5, "F"), 0, "S")
Next
End Sub

--
I Tried with Above VBA code, Not Getting
Eg: 1.550 , Shown only : A.FF, To be Shown : A.FFS
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