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Default Tier As Range Function

Make sure you ask in nice order (like P45Cal said):

Select Case ERNVAR
Case Is < -0.12: FINDTier = Tier(8)
Case Is <= -0.07: FINDTier = Tier(7)
Case Is <= -0.03: FINDTier = Tier(6)
Case Is <= 0: FINDTier = Tier(5)

'what happens between 0 and .05???

'.13 is duplicated in your code
'which tier did you want?
Case Is 0.13: FINDTier = Tier(1)
Case Is = 0.13: FINDTier = Tier(2)

Case Is = 0.09: FINDTier = Tier(3)
Case Is = 0.05: FINDTier = Tier(4)

End Select

But that mixture of < and makes the code difficult for me.

This makes my head spin much less:

Select Case ERNVAR
Case Is < -0.12: FINDTier = Tier(8)
Case Is <= -0.07: FINDTier = Tier(7)
Case Is <= -0.03: FINDTier = Tier(6)
Case Is <= 0: FINDTier = Tier(5)

Case Is < 0.05: FINDTier = "Not defined"

Case Is < 0.09: FINDTier = Tier(4)
Case Is < 0.13: FINDTier = Tier(3)
Case Else
FINDTier = Tier(1)
End Select

Kind of like a postage stamp function. As soon as your package hits a certain
weight, it's categorized one way. And all packages that don't exceed the next
limit are the same price as your package.





Jim wrote:

I am trying to understand why this function is producing weird
results. I feel like I have setup the function correctly, but the
numbers being returned are not the numbers expected. Thanks for the
help,

Function FINDTier(ERNVAR, Tier As Range)

Select Case ERNVAR

Case Is 0.13: FINDTier = Tier(1)
Case Is = 0.13: FINDTier = Tier(2)
Case Is = 0.09: FINDTier = Tier(3)
Case Is = 0.05: FINDTier = Tier(4)
Case Is <= 0: FINDTier = Tier(5)
Case Is <= -0.03: FINDTier = Tier(6)
Case Is <= -0.07: FINDTier = Tier(7)
Case Is < -0.12: FINDTier = Tier(8)
End Select

End Function


--

Dave Peterson
 
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