its a type of defect of a specific product or products.
there are so many types of defects that one can find (1-226) and from
that it gets narrowed down even more (1-22)

On May 12, 8:52*am, John wrote:
I'd be interested in knowing what sort of thing this is your making.
What's it for?

Why can't you use Select Case somehow?

Case pp36,p44,pp45,pp46 : Cells(whatever) = 1
Case pp37,pp38,pp39,pp54,pp55 : Cells(whatever) = 3
and so on

JOhn



wrote:
ok well i have a set of numbers from 1 through 226 and i have broken
them down to a set where they have to equal a set between 1 and 22.

the numbers between 1 and 226 have a pp in front of them always.

pp124
pp23
pp78
pp90

On May 8, 11:46 am, Mike H. wrote:
No idea what you mean. *Please give explicit example so I can follow which
number you're talking about.

" wrote:
i forgot to mention that there are words in tied with the numbers. the
2 letters in front the the number then several words after
On May 7, 12:47 pm, Mike H. wrote:
This is quite easy then. *In the code when you put the data in sheet2, just
put this code in column x, where x is the column your number goes, assuming
the other number is to the left:
So you have your calculation in your code:
let x=1 *'Or start with the new row # only
let Y=the column where the number is
let Z=the column where you want your calculation to go
do while true
* *if cells(x,y).value=empty then exit do
* *if cells(x,Y).value=36 or cells(x,y).value=44 or cells(x,y).value=45 or
cells(x,y).value=46 then
* * * * let cells(x,z).value=1
* *elseif cells(x,y).value=37 then *'(and the other values for 3)
* * * * let cells(x,z).value=3
* *etc.etc.etc....
* *end if
* *x=x+1
Loop
" wrote:
no luck finding what i need. sorry.
i have a database on sheet1 that data is transfered into a diffrent
database on sheet2.
using vba coding.
on a column in sheet2 is where i need the formula or vba to make the
matchup
On May 7, 10:39 am, Mike H. wrote:
This would be a whole lot easier to do if you did it via VBA in code instead
of a formula. *You'd have to have the code determine if the cell that was
last changed was one of the "number" cells. *Then you'd do your analysis:
if Thatcell=36 then
* *Thatcell.column+1=1
elseif Thatcell=44 then
* *Thatcell.column+1=1
etc.....
You should be able to find examples for doing this in other postings. *If
not, let me know and I can set you up...
" wrote:
i have this formula so i can seperate a set of number when needed. for
example a selected amount of diffrent numbers will equal a specific
number. *i need to add more to this formula so i can have it
completed.
=IF(OR(--MID(B1,3,3)={31,32,33,34,85,86,139,140,141}),LOOKU P(--
MID(B1,3,1),*{1,3,8},{15,12,14}),IF(AND(--MID(B1,3,3)213,--
MID(B1,3,3)<227),10,IF(OR(--*
MID(B1,3,3)={19,21,22,24,25,26,27,28,29,30,35}),13 ,IF(OR(AND(--
MID(B1,3,3)*145,--MID(B1,3,3)<160),AND(--MID(B1,3,3)200,--
MID(B1,3,3)<208)),6,IF(OR(AN*D(--MID(B1,3,3)62,--
MID(B1,3,3)<79),AND(--MID(B1,3,3)86,--MID(B1,3,3)<92)*,AND(--
MID(B1,3,3)96,--MID(B1,3,3)<136)),11,1+INT((--MID(B1,3,3)-1)/
10))))*))
this the set of numbers. the ones on the right have to equal the ones
on the left.
1= 36,44,45,46
3= 37,38,39,54,55
5= 40-43
6= 47,48,49, 146-159, 201-210
7= 23, 83,84, 211
10= 212,214, 227
11= 57-82, 87-136, 163,167, 199, 213
12= 31-34
13= 21,22, 24-30, 160-197
14= 85,86
15= 139-141
16= 1,2,13,14,17,18,53
17= 3,4,15,16,20
19= 50,51,52
20= 19
22= 142-145
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