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Hello Gary,
I tried your code. It stops with the last cell just before the 1st filtered/hidden row. I posted the following in reply to Jim's post (earlier in tread). Dim i As Long i = Selection.Areas.Count MsgBox Selection.Areas(i).Item(Selection.Areas(i).CountLa rge).Address I think it is not properly written, but it is working. -- Thank you for your help. MSweetG222 "Gary Keramidas" wrote: does this work if typed in the immediate window? Debug.Print Selection.Range("A1").Offset(Selection.Rows.Count - 1, Selection.Columns.Count - 1).Address -- Gary "MSweetG222" wrote in message ... I am trying to determine the cell address of the cell in the lower right corner of the selected range. I tried the code from David McRitchie's website (modified slightly, I changed code from denoted address on the spreadsheet to displaying address in a msgbox). The code works okay in Excel 2003, but when selecting a larger region in Excel 2007, I receive an overflow issue. Assume the range selected is A:FFF Sub MarkSepAreas() 'David McRitchie 1999-06-03 Mark cells with cell address and 'area number. Enhanced based on Alan Beban code 1999-06-03. 'Documented with Join() 'in http://www.mvps.org/dmcritchie/excel/join.htm Application.ScreenUpdating = False Application.Calculation = xlCalculationManual Dim i As Long, j As Long For i = 1 To Selection.Areas.Count For j = 1 To Selection.Areas(i).Count x = Selection.Areas(i)(j).AddressLocal(0, 0) MsgBox x Next Next Application.Calculation = xlCalculationAutomatic Application.ScreenUpdating = True End Sub -- Thank you for your help. MSweetG222 |
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