Home |
Search |
Today's Posts |
#1
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Hey all,
I can set a filename with sFileName = Application.GetOpenFilename Is there a similar way to set the path as a variable? Currently I am using a command: Set oDoc = oAPP.OpenDataDoc("C:\January\File.xls") with a bunch of editting to File.xls I would like to change this to Set oDoc = oAPP.OpenDataDoc(strPATH + "File.xls") where I have opened some sort of dialog to set the Path for the current month. Thanks in advance, Lance |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
specify default path in dialog open box | Excel Programming | |||
dialog box to pick path & file | Excel Programming | |||
open dialog box for file path | Excel Programming | |||
GetOpenFilename Dialog default path | Excel Programming | |||
Getting the full path when from a File Open Dialog Box | Excel Programming |