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Your file is probably a binary file. I included the VBA help instruction for
the OPEN and INPUT functions. I would try to open the file in BINARY mode. Ther are tips in the help below on using LEN with Binary files. ---------------------------------------------------------------------------------------------- Open Statement Enables input/output (I/O) to a file. Syntax Open pathname For mode [Access access] [lock] As [#]filenumber [Len=reclength] The Open statement syntax has these parts: Part Description pathname Required. String expression that specifies a file name €” may include directory or folder, and drive. mode Required. Keyword specifying the file mode: Append, Binary, Input, Output, or Random. If unspecified, the file is opened for Random access. access Optional. Keyword specifying the operations permitted on the open file: Read, Write, or Read Write. lock Optional. Keyword specifying the operations restricted on the open file by other processes: Shared, Lock Read, Lock Write, and Lock Read Write. filenumber Required. A valid file number in the range 1 to 511, inclusive. Use the FreeFile function to obtain the next available file number. reclength Optional. Number less than or equal to 32,767 (bytes). For files opened for random access, this value is the record length. For sequential files, this value is the number of characters buffered. Remarks You must open a file before any I/O operation can be performed on it. Open allocates a buffer for I/O to the file and determines the mode of access to use with the buffer. If the file specified by pathname doesn't exist, it is created when a file is opened for Append, Binary, Output, or Random modes. If the file is already opened by another process and the specified type of access is not allowed, the Open operation fails and an error occurs. The Len clause is ignored if mode is Binary. Important In Binary, Input, and Random modes, you can open a file using a different file number without first closing the file. In Append and Output modes, you must close a file before opening it with a different file number. ---------------------------------------------------------------------------------------------- Input Function Returns String containing characters from a file opened in Input or Binary mode. Syntax Input(number, [#]filenumber) The Input function syntax has these parts: Part Description number Required. Any valid numeric expression specifying the number of characters to return. filenumber Required. Any valid file number. Remarks Data read with the Input function is usually written to a file with Print # or Put. Use this function only with files opened in Input or Binary mode. Unlike the Input # statement, the Input function returns all of the characters it reads, including commas, carriage returns, linefeeds, quotation marks, and leading spaces. With files opened for Binary access, an attempt to read through the file using the Input function until EOF returns True generates an error. Use the LOF and Loc functions instead of EOF when reading binary files with Input, or use Get when using the EOF function. Note Use the InputB function for byte data contained within text files. With InputB, number specifies the number of bytes to return rather than the number of characters to return. "Per" wrote: -- Per "Joel" skrev: I got the code to work by commented out the chdir. I did not get the same error you had. I think the problem is with the permnissions of the directory you are using. I would add the following code to help locate the problem msgbox(Application.Path) <= find out which path you are using. ChDir IndataKatalog For some reason I don't understand it doesn't work on my computer. I have modified the program code so that I can read the file from the same directory as the workbook is stored in and also in the same directory as the msgbox(Application.Path) shows but nothing seems to help. Per |
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