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Hi,
I'm hoping someone can help with a very simple problem. I have a column in excel that contains numbers of 9 digits each. I have an access table containing these numbers and a lot of additional information. I am trying to execute a query through code, that will return this additional data. I have made the query work by going down each line in excel and opening a new query and pulling back the information WHERE the article number = a variable containing the number from excel. This works fine but is slow. What I would like to do is build a string containing all the article numbers, to act as a multiple criteria WHERE query. I have had this work when I have used the numbers directly, but when I try it through code, I get a "Type mismatch" error as soon as the macro reaches the query. Below is the string building and query code. Can anyone point out why this is not working? saparticle = ActiveCell criteriastring = "(`Final Output`.Article='" & saparticle & "') " While ActiveCell.Offset(1, 0) < "" ActiveCell.Offset(1, 0).Select saparticle = ActiveCell criteriastring = criteriastring & "OR (`Final Output`.Article='" & saparticle & "') " Wend Range("R4").Name = "onedctarget" With ActiveSheet.QueryTables.Add(Connection:=Array(Arra y( _ "ODBC;DSN=MS Access Database;DBQ=H:\*******.mdb;DefaultDir=H: \*****;DriverId=281;FIL=MS Access;MaxBuffe" _ ), Array("rSize=2048;PageTimeout=5;")), Destination:=Range("onedctarget")) .CommandText = Array( _ "SELECT `Final Output`.Article,`Final Output`.Site,`Final Output`.Listed, `Final Output`.OneDC" & Chr(13) & "" & Chr(10) & "FROM `H:\****`.`Final Output` `Final Output`" & Chr(13) & "" & Chr(10) & "WHERE " & criteriastring) .Name = "Query from MS Access Database" .FieldNames = False .RowNumbers = False .FillAdjacentFormulas = False .PreserveFormatting = False .RefreshOnFileOpen = False .BackgroundQuery = False .RefreshStyle = xlOverwriteCells .SavePassword = False .SaveData = False .AdjustColumnWidth = False .RefreshPeriod = 0 .PreserveColumnInfo = False .Refresh BackgroundQuery:=False End With Any help would be much appreciated. Thanks, Dan |
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