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Unique Data ID tags help (average)
To all,
I have a load of data for different locations eg: B4 at1000°C(1) = 98 B4 at1000°C(2) = 88 B4 at1000°C(3)= 88 C4 at777°C(1)= 23 C4 at777°C(2)= 22 B5 at1000°C(2)= 19 What I want to be able to do is analyse the data id number i.e. C4 at777°C and then average all the data for that location, in this case ( 22 +23)/2. etc. and then give an output of C4 at777°C= 22.5 etc. I guess that I have to search through the data and create a set of unique data ids, in this case would be B4 at 1000, C4 at 777, and B5 at 1000, and then define these as variables and re search through the data to get the averages? Any Ideas. The number of locations ( data id ) can change and is not constant. Thanks in advance for your help, Regards Joseph Crabtree |
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Unique Data ID tags help (average)
Hi
The source data: the location and temp in column A i.e. B4 at1000°C(1) , and the value. i.e. 98 in column B. I have dont have multiple data items in each cell. Just a location and temperature in column A, and a balue in column B. Any ideas, Thanks Joseph Jim Thomlinson wrote: So what exactly does your source data look like? You may be able to use a pivot table to get exactly what you want including coming up with all of the unique groupings... Do you have multiple data items in each cell or ??? -- HTH... Jim Thomlinson "joecrabtree" wrote: To all, I have a load of data for different locations eg: B4 at1000°C(1) = 98 B4 at1000°C(2) = 88 B4 at1000°C(3)= 88 C4 at777°C(1)= 23 C4 at777°C(2)= 22 B5 at1000°C(2)= 19 What I want to be able to do is analyse the data id number i.e. C4 at777°C and then average all the data for that location, in this case ( 22 +23)/2. etc. and then give an output of C4 at777°C= 22.5 etc. I guess that I have to search through the data and create a set of unique data ids, in this case would be B4 at 1000, C4 at 777, and B5 at 1000, and then define these as variables and re search through the data to get the averages? Any Ideas. The number of locations ( data id ) can change and is not constant. Thanks in advance for your help, Regards Joseph Crabtree |
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