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Open file in VBA
Hello,
When I walk through the following statement I get a run time error 1004 that says that the particular file couls not be found. I used the following statement: sFilename = Dir("H:\Risk_Management\Special_Review\Upload_file s\*.xls") Workbooks.Open Filename:=sFilename Do I forgot something? Thanks for your assistance!! Rgds, Robert |
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