Open file in VBA
Hello,
When I walk through the following statement I get a run time error 1004
that says that the particular file couls not be found.
I used the following statement:
sFilename = Dir("H:\Risk_Management\Special_Review\Upload_file s\*.xls")
Workbooks.Open Filename:=sFilename
Do I forgot something?
Thanks for your assistance!!
Rgds,
Robert
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